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3 years ago

What is the equation of the line written in general form?

Mathematics

2 answers:

yanalaym [24]3 years ago

7 0

Answer:

Step-by-step explanation:

It intersects at the y-axis at +2 so it's ax+2 so far.

The slope is 1 because for every 1 coordinate added on the x-axis, one is subtracted from he y-axis.

This leaves us with this equation: 1x+2, but the coefficient isn't needed because it is one.

The answer:

y=x+2

makkiz [27]3 years ago

5 0

Answer:

x+y-2=0

Step-by-step explanation:

In order to solve this you just have to see the values on the axis interesection as you can see the intersect with the Y axis is located ad (0,2) and with the X axis is at (2,0), so from the options we have to evaluate those options for when the equation is at that point:

-x+y-2=0

-x+2-2=0

-x=0

This can not be true so that´s wrong

x+y-2=0

x+2-2=0

x=0

Since x= o in the graph when y=2 this is our correct option.

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What is the area of the rectangle? rectangle on a coordinate plane. rectangle has vertices at begin ordered pair 1 comma 3 end o

miv72 [106K]

<span>it is the letter b because if you count closly you will see

</span>

7 0

3 years ago

Solve this problem using the Distributive Property.<br><br> 2 ( 7 + 8 ) =

maria [59]

Answer:

Step-by-step explanation:

Original Equation: 2(7 + 8)

So you have to multiply 2 by 7 which equals 14

Then you multiply 2 by 8 which equals 16

Your equation should now look like this: 14 + 16

Add 14 and 16 together.

Your answer is 30

Hope I helped :)

Please condsider brainliest

7 0

3 years ago

Heyy! i’ll give brainliest help asap pls

vladimir1956 [14]

Answer:

I think it's A

hope this helps

have a good day :)

Step-by-step explanation:

7 0

2 years ago

Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui

Vesnalui [34]

<h3>The dimensions of the given rectangular box are:</h3><h3>L = 15.874 cm , B = 15.874 cm , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box

= Area of the base + 4 x ( Area of the adjacent faces)

= S x S + 4 ( S x H) = S² + 4 SH ..... (1)

Also, Area of the box = S x S x H = S²H

⇒ S²H = 2000

$\implies H = \frac{2000}{S^2}$

Substituting the value of H in (1), we get:

$A = S^2 + 4 SH = S^2 + 4 S(\frac{2000}{S^2}) = S^2 + (\frac{8000}{S})\\\implies A = S^2 + (\frac{8000}{S})$

Now, to minimize the area put :

$(\frac{dA}{dS} ) = 0 \implies 2S - \frac{8000}{S^2} = 0\\\implies S^3 = 4000\\\implies S = 15.874 \approx 16 cm$

Putting the value of S = 15.874 cm in the value of H , we get:

$\implies H = \frac{2000}{S^2} = \frac{2000}{(15.874)^2} = 7.8937 cm$

Hence, the dimensions of the given rectangular box are:

L = 15.874 cm

B = 15.874 cm

H = 7.8937 cm

3 0

3 years ago

Problem PageQuestion Tony estimated the height of his office building to be 45ft. The actual height of his office building is 41

Leona [35]

Answer:

The absolute error is <u>4 ft</u> and percent error of Tony's estimate is <u>9.8%</u>.

Step-by-step explanation:

Given:

Tony estimated the height of his office building to be 45ft. The actual height of his office building is 41ft.

Now, to find the absolute error and the percent error of Tony's estimate.

The height of his office building = 45ft.

The actual height of his office building = 41 ft.

So, to get the absolute error:

<em>The height of his office building - the actual height of his office building</em>

$45\ ft-41\ ft\\=4\ ft.$

The absolute error = 4 ft.

Now, to get the percent error of Tony's estimate:

$\frac{4}{41} \times 100$

$=0.0975\times 100$

$=9.75\%.$

<em>Percent error of Tony's estimate rounding to nearest tenth = 9.8%.</em>

Therefore, the absolute error is 4 ft and percent error of Tony's estimate is 9.8%.

5 0

3 years ago

What is the equation of the line written in general form?​

What is the equation of the line written in general form?