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Lana71 [14]
2 years ago
11

What is an equation of the line that passes through the point (-5,2)(−5,2) and is parallel to the line 4x-5y=54x−5y=5?

Mathematics
1 answer:
masya89 [10]2 years ago
4 0

Answer:

well you said the answer is five so five

Step-by-step explanation:

4×-5y=54×-5y=5

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mel-nik [20]
1.  79%  Take 100 x 21%=21, then subtract 21 from 100 = 79
2.  $138  Take 1200 x 11.5%= $138
3 0
3 years ago
Given the following definition, compute Q(5). Q(n) = 0 if n = 0 2 if n = 1 4 if n = 2 Q(n − 1) + Q(n − 2) + Q(n − 3) if n > 2
aalyn [17]
We have 
Q(0)=0\\
Q(1)=2\\
Q(2)=4
and Q(n)=Q(n-1)+Q(n-2)+Q(n-3)\mbox{ when } n\ \textgreater \ 2.
So 
Q(3)=Q(2)+Q(1)+Q(0)=4+2+0=6\\
Q(4)=Q(3)+Q(2)+Q(1)=6+4+2=12\\
Q(5)=Q(4)+Q(3)+Q(2)=12+6+4=22.

3 0
2 years ago
What is the answer to #3?
FrozenT [24]
I think it’s 2 but I’m not sure
5 0
2 years ago
How do you find the <br> y-intercept and the slope for number 11
Sophie [7]
The first step is to find the slope. Use the slope formula

m = (y2-y1)/(x2-x1)

The two points are (x1,y1) = (-1,5) and (x2,y2) = (2,-1)

So,
x1 = -1
y1 = 5
and
x2 = 2
y2 = -1
will be plugged into the slope formula to get...
m = (y2-y1)/(x2-x1)
m = (-1-5)/(2-(-1))
m = (-1-5)/(2+1)
m = (-6)/(3)
m = -2

The slope is -2

Use m = -2 and one of the points to find the y intercept b. I'll use the point (x,y) = (-1,5) ---> x = -1, y = 5

y = mx+b ... slope intercept form
5 = -2*(-1)+b
5 = 2+b
5-2 = 2+b-2
3 = b
b = 3

The y intercept is 3

-----------------------------------

m = -2 is the slope
b = 3 is the y intercept

Therefore y = mx+b turns into y = -2x+3 as the equation that goes through the two points
6 0
3 years ago
Factor the expression. 48g2 – 22gh – 15h2
Anit [1.1K]
The answer is (6g-5h)(8g+3h)
6 0
3 years ago
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