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Wewaii [24]
3 years ago
10

Find the 11th term of the sequence 11, 19, 27, 35

Mathematics
1 answer:
iragen [17]3 years ago
7 0

Answer:

  91

Step-by-step explanation:

Each term is 8 more than the last, so you can write the terms of the sequence until you get there:

  11, 19, 27, 35, 43, 51, 59, 67, 75, 83, 91

__

Or, you can use the formula for the general term of an arithmetic sequence. You have first term a1=11 and common difference d=8.

  an = a1 +d(n -1)

  a11 = 11 + 8(11 -1) = 11 + 80

  a11 = 91

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