All categories

3 years ago

Explain how to fin 4 x 80. show your work

Mathematics

1 answer:

algol [13]3 years ago

5 0

4x80=320

Work:

4x8 = 32
(4+4+4+4+4+4+4+4)
Now carry the 0 and you get 320

You might be interested in

Write two linear expressions that have a sum of 3x-8

irakobra [83]

1. (5x + 2 )
2. ( -2x -10 )

5 0

3 years ago

Read 2 more answers

Here's a graph of a linear function. Write the equation that describes that function. 8 Express it in slope intercept form. Ente

Stolb23 [73]

Answer:

f(x) = $\frac{1}{2}x+4$

Step-by-step explanation:

Let the equation of the function is,

f(x) = mx + b

Here, m = slope of the line

b = y-intercept

From the graph attached,

y-intercept 'b' = 4

Slope = $\frac{\text{Rise}}{\text{Run}}$

= $\frac{4}{8}$

= $\frac{1}{2}$

Therefore, equation of the function representing the graph will be,

f(x) = $\frac{1}{2}x+4$

5 0

3 years ago

Penny caught a fish that weighed 2.9 lbs. The fish Harold caught weighs 60%

IrinaVladis [17]

Answer:

4.64

Step-by-step explanation:

2.9 x 1.60=4.64

3 0

2 years ago

The directions says determine weather each rate of change is consistent. If it is, find the rate of change and explain what it r

Whitepunk [10]

3:1 is your answer bruuuuuuhhhh

4 0

3 years ago

Read 2 more answers

How much should a family deposit at the end of every 6 months in order to have $4000 at the end of 3 years? The account pays 5.9

ra1l [238]

We are asked to determine the present value of an annuity that is paid at the end of each period. Therefore, we need to use the formula for present value ordinary, which is:

$PV_{ord}=C(\frac{1-(1+i)^{-kn}}{\frac{i}{k}})$

Where:

$\begin{gathered} C=\text{ payments each period} \\ i=\text{ interest rate} \\ n=\text{ number of periods} \\ k=\text{ number of times the interest is compounded} \end{gathered}$

Since the interest is compounded semi-annually this means that it is compounded 2 times a year, therefore, k = 2. Now we need to convert the interest rate into decimal form. To do that we will divide the interest rate by 100:

$\frac{5.9}{100}=0.059$

Now we substitute the values:

$PV_{ord}=4000(\frac{1-(1+0.059)^{-2(3)}}{\frac{0.059}{2}})$

Now we solve the operations, we get:

$PV_{\text{ord}}=39462.50$

Therefore, the present value must be $39462.50

8 0

1 year ago