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kkurt [141]
3 years ago
8

Can someone plz help me solved this problem I need help plz help me! Will mark you as brainiest!

Mathematics
1 answer:
shusha [124]3 years ago
6 0

Answer:

11

4

Step-by-step explanation:

3 hrs to travel 45 miles downstream

4 hrs to travel 28 miles upstream

speed of boat in still water= s

speed of the current= c

  • s+c= 45/3= 15
  • s-c= 28/4=7

added up the 2 equations, we get:

  • 2s= 22
  • s= 11 mph
  • c= 4 mph
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Answer:

1. false

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Step-by-step explanation:

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On the 1st Jan 2012 Beth invested some money into a bank account.The account pays 2.5% interest per year.On the 1st Jan 2013 she
pshichka [43]

Answer:

On the 1st Jan 2012 Beth invested some money into a bank account.The account pays 2.5% interest per year.On the 1st Jan 2013 she withdraws £1000.

Step-by-step explanation:

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For the parallelogram ABCD the extensions of the angle bisectors AG and BH intersect at point P. Find the area of the parallelog
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Answer:

The area of a parallelogram is 360 in.²

Step-by-step explanation:

Where DG = GH

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AB = 39 in.

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Whereby ∠DAB is bisected by AG and ∠ABC is bisected by BH

Therefore, ∠GAB + ∠HBA = 90°

Hence, ∠BPA = 90° (Sum of interior angles of a triangle)

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{AP}{39} = \dfrac{GP}{GH} =\dfrac{12}{GH}

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Hence AD = DG (Side length of isosceles triangle)

The bisector of ∠ADG is parallel to BH and will bisect AG at point Q

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Hence, AP = 3 × GP = 3 × 12 = 36

cos(\angle GAB) = \dfrac{AP}{AB} = \dfrac{36}{39}

\angle GAB = cos^{-1} \left (\dfrac{36}{39}  \right )

∠GAB = 22.62°

cos(\angle GAB) =  \dfrac{36}{39} = \dfrac{12}{GH}

GH =  \dfrac{39}{36} \times {12}

GH = 13 in.

∴ AD 13 in.

BP = 39 × sin(22.62°) = 15 in.

GH = √(GP² + HP²)

∠DAB = 2 × 22.62° = 45.24°

The height of the parallelogram = AD × sin(∠DAB) =  13 × sin(45.24°)

The height of the parallelogram = 120/13 =  9.23 in.

The area of a parallelogram = Base × Height = (120/13) × 39 = 360 in.²

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