Find the density of a metal if 100cm weighs 800 grams.

A random sample of 700 home owners in a particular city found 112 home owners who had a swimming pool in their backyard. Find a

vekshin1

Answer: $(13.28\%,\ 18.72\%)$

Step-by-step explanation:

Given : A random sample of 700 home owners in a particular city found 112 home owners who had a swimming pool in their backyard.

i.e. n= 700 and x= 112

Sample proportion : $\hat{p}=\dfrac{x}{n}=\dfrac{112}{700}=0.16$

z-value for 95% confidence interval : $z_c=1.960$

Now, the 95% confidence interval for the true percent of home owners in this city who have a swimming pool in their backyard will be :-

$\hat{p}\pm z_c\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$=0.16\pm (1.96)\sqrt{\dfrac{0.16(1-0.16)}{700}}$

$=0.16\pm (1.96)(0.013856)\\\\\approx 0.16\pm0.0272\\\\ =(0.16-0.0272,\ 0.16+0.0272)=(0.1328,\ 0.1872)=(13.28\%,\ 18.72\%)$

Hence, 95% confidence interval for the true percent of home owners in this city who have a swimming pool in their backyard : $(13.28\%,\ 18.72\%)$

6 0

3 years ago

I need help with this!! I need to solve it using order of operations

taurus [48]

The answer to number 1 is 16, because it the equation would be simplified to this...

32 + 4 - 20 = 36 - 20 = 16

The 3rd answer is 551...

(-125+11)(-5)-19=579-19=551

The 5th answer is 29383...

-17×1728=29383...

Hope this helps!!!

4 0

3 years ago

A landscaper needs 348 pounds of plant food. He has 114 pounds in his truck, and another 46 pound at his shop.

Black_prince [1.1K]

Answer:

$\frac{19}{12}\ pounds$

or

$1\frac{7}{12}\ pounds$

Step-by-step explanation:

<u><em>The correct question is </em></u>

A landscaper needs 3 4/8 pounds of plant food. He has 1 1/4 pounds in his truck, and another 4/6 pound at his shop. How many more pounds of plant food does the landscaper need?

Let

x ----> the additional pounds of plant food needed for the landscaper

we know that

The additional pounds of plant food needed for the landscaper plus the pounds in his truck plus the pounds in his shop must be equal to the total pounds of plant food needed

so

The linear equation that represent this problem is

$x+1\frac{1}{4}+\frac{4}{6}=3\frac{4}{8}$

Convert mixed number to an improper fractions

$1\frac{1}{4}=1+\frac{1}{4}=\frac{4*1+1}{4}=\frac{5}{4}$

$3\frac{4}{8}=3+\frac{4}{8}=\frac{3*8+4}{8}=\frac{28}{8}=\frac{14}{4}$

Substitute in the expression above

$x+\frac{5}{4}+\frac{4}{6}=\frac{14}{4}$

solve for x

Multiply by (4*6) both sides to remove the fractions

$24x+30+16=84$

Combine like terms left side

$24x+46=84$

subtract 46 both sides

$24x=84-46$

$24x=38$

Divide by 24 both sides

$x=\frac{38}{24}\ pounds$

simplify

$x=\frac{19}{12}\ pounds$

Convert to mixed number

$\frac{19}{12}\ pounds=\frac{12}{12}+\frac{7}{12}=1\frac{7}{12}\ pounds$

4 0

3 years ago

Select all the values of m that make the inequality m<7.4 true. 7.40, 7.62, 6.8, 7.09, 8.1.

Ipatiy [6.2K]

Answer:

hellloooooooooooo

Step-by-step explanation:

thx

4 0

3 years ago

Read 2 more answers

Suppose you just purchased a digital music player and have put 15 tracks on it. After listening to them you decide that you like

blsea [12.9K]

Answer:

Total songs = 15

Liked songs = 3

Un liked songs = 15-3=12

Find the probability that among the first two songs played

(a) You like both of them.

Probability that among the first two songs played you like both of them = $\frac{3}{15} \times \frac{2}{14} = 0.029$

(b) You like neither of them.

Probability that among the first two songs played you like neither of them = $\frac{12}{15} \times \frac{11}{14} = 0.629$

(c) You like exactly one of them.

Probability that among the first two songs played you like exactly one of them = $\frac{3}{15} \times \frac{12}{14}+ \frac{12}{15} \times \frac{3}{14}= 0.343$

(d) Redo (a)-(c) if a song can be replayed before all

(a) You like both of them. Would this be unusual?

Probability that among the first two songs played you like both of them = $\frac{3}{15} \times \frac{3}{15} = 0.04$

(b) You like neither of them.

Probability that among the first two songs played you like neither of them = $\frac{12}{15} \times \frac{12}{15} = 0.64$

(c) You like exactly one of them.

Probability that among the first two songs played you like exactly one of them = $\frac{3}{15} \times \frac{12}{15}+ \frac{12}{15} \times \frac{3}{15}= 0.32$

7 0

4 years ago

Find the density of a metal if 100cm weighs 800 grams.​

Find the density of a metal if 100cm weighs 800 grams.