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3 years ago

14

The length of a rectangular portrait is 1.5 times the width. The perimeter is 10 feet.

1 answer:

disa [49]3 years ago

8 0

In order to solve the problem above, represent the width by x. With this, the length of the rectangular portrait is 1.5x. The perimeter of the rectangle is two times the sum of the length and width. This translates to,

2 (1.5x + x) = 10 ft, x = 2 ft.

Thus, the length of the rectangular portrait is 3 ft.

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Is 2.81 an irrational number

nekit [7.7K]

Answer:

No.

Step-by-step explanation:

It can be written as 2 81/100 or 281/100 so it is not irrational. An irrational number is a number that cannot be written as a ratio of two numbers

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3 years ago

Read 2 more answers

357,335 rounded to the nearest ten357,335 rounded to the nearest ten

Advocard [28]

Answer:

357,340

Step-by-step explanation:

Locate the tens place:

357,3<u>3</u>5

Check the number to the right:

357,33<u>5 </u>

<u></u>

If the number is greater than or equal to 5, then we round up. If the number is less than or equal to 4, we round down.

The number next to the tens place is a '5'. We round up.

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Hope this helps.

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3 years ago

Please help me with thiss

olchik [2.2K]

Answer:

gradient = 2

Step-by-step explanation:

Calculate the gradient (slope) m using the slope formula

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with (x₁, y₁ ) = (1, 0) and (x₂, y₂ ) = (6, 10) ← 2 points on the line

m = $\frac{10-0}{6-1}$ = $\frac{10}{5}$ = 2

3 0

2 years ago

What is the area of the composite shape below?

solmaris [256]

I might be wrong but it might be 62

4 0

3 years ago

The radius of this ball is 15 inches. Which equation gives the ball's surface area, in square inches?

victus00 [196]

Answer:

$\large\boxed{S.A.=4500\pi\ in^2\approx14130\ in^2}$

Step-by-step explanation:

The formula of a surface area of a ball (sphere):

$S.A.=\dfrac{4}{3}\pi R^3$

R - radius

We have R = 15in. Substitute:

$S.A.=\dfrac{4}{3}\pi(15^3)=\dfrac{4}{3}\pi(3375)=4500\pi\ in^2$

If you want to get an approximation, then:

$\pi\approx3.14\\\\S.A.\approx(4500)(3.14)=14130\ in^2$

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3 years ago