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Savatey [412]
4 years ago
14

The length of a rectangular portrait is 1.5 times the width. The perimeter is 10 feet.

Mathematics
1 answer:
disa [49]4 years ago
8 0
In order to solve the problem above, represent the width by x. With this, the length of the rectangular portrait is 1.5x. The perimeter of the rectangle is two times the sum of the length and width. This translates to, 

                                    2 (1.5x + x) = 10 ft, x = 2 ft.

Thus, the length of the rectangular portrait is 3 ft. 
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Which number sentence is true? A. –39.6 ÷ 4.8 = 8.25 B. –39.6 ÷ (–4.8) = –8.25 C. 39.6 ÷ –4.8 = 8.25 D. –39.6 ÷ (–4.8) = 8.25
Ahat [919]

Answer:

A) 39.6 divided by 8.25 is true.

5 0
3 years ago
At soccer camp, Belle spent 30 minutes practicing defense and 1 hour and 15 minutes shooting. If the camp ended at 12:15 P.M., w
SVEN [57.7K]

Answer:

10:30 A.M.

Step-by-step explanation:

12:15 P.M. -

01:15 =

11:00 A.M. -

00:30 =

10:30 A.M.

3 0
3 years ago
1/3 in division form
marusya05 [52]

Answer:

Remember, 3 is the same thing as 3/1. Before we can divide, we need to make one more change. We'll switch the numerator and the denominator of the fraction we're dividing by: 1/3 in this example. So 1/3 becomes 3/1.

Step-by-step explanation:

:)

8 0
4 years ago
The regular price of an item is $84. The item was on cell with a discount of $12 what is the discount rate
Sunny_sXe [5.5K]

Answer:

<em>The discount is 14.3%.</em>

Step-by-step explanation:

Regular price: $84

Discount: $12

We need to find what percent of $84 is $12.

To find what percent a part is of a whole, divide the part by the whole and multiply by 100.

12/84 * 100% = 14.2857...%

Answer: 14.3%

4 0
3 years ago
use four rectangles to estimate the area between the graph of the function and the x-axis on the interval using the right endpoi
WINSTONCH [101]

we have the function

f(x)=6/(7x)

the interval [2,6]

Divide into fur rectangles

the width of each rectangle is equal to

(6-2)/4=1

the intervals are

(2,3) (3,4) (4,5) and (5,6)

using the right endpoints

the approximate area is equal to

A1=f(3)*(1)=[6/(7*3)]*(1)=6/21

A2=f(4)*(1)=[6/(7*4)]*(1)=6/28

A3=f(5)*(1)=[6/(7*5)]*(1)=6/35

A4=f(6)*(1)=[6/(7*6)]*(1)=6/42

therefore

the approximate area is

A=(6/21)+((6/28)+(6/35)+(6/42)

simplify

A=(6/7)*[(1/3)+(1/4)+(1/5)+(1/6)]

A=(6/7)*[(20+15+12+10)/60]

A=(6/7)*[57/60]

<h2>A=57/70 unit2 -----> exact answer</h2>
4 0
1 year ago
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