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3241004551 [841]
2 years ago
14

Five less than one half of a number is 18. 5 – = 18 1/2 – 5 18 x – 5 = 18 5- X = 18

Mathematics
1 answer:
arsen [322]2 years ago
8 0

Answer:

x-5=18 because x would be the number with "5 less"  being the "-5."

Hoped I helped

mark me as brainliest

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In this figure m&lt;3=130 <br> What is m&lt;6 ?
Georgia [21]

Answer: m\angle6=50\°

Step-by-step explanation:

You can observe in the figure two parallel lines that are intersected by a transversal and several angles are formed.

The angles m∠3 and m∠6 are located inside the parallel lines and on one side of the transversal, this angles are known as "Consecutive interior angles" and they are supplementary (which means that they add up 180°).

Therefore, you know that:

m\angle3+m\angle6=180\°

So you can substitute m∠3=130° and solve for m∠6. Then you get:

130\°+m\angle6=180\°\\m\angle6=180\°-130\°\\m\angle6=50\°

4 0
3 years ago
Read 2 more answers
Solve the problem. For large numbers of degrees of​ freedom, the critical chi χ squared 2 values can be approximated using the f
kykrilka [37]

Answer:

0.01  =0.0001

Step-by-step explanation:

7 0
3 years ago
Find slope of the graph 9x-3y=15
LekaFEV [45]
<h3><u>Explanation</u></h3>
  • Convert the equation into slope-intercept form.

y = mx + b

where m = slope and b = y-intercept.

What we have to do is to make the y-term as the subject of equation.

9x - 3y = 15 \\ 9x - 15 = 3y \\  \frac{9x - 15}{3}  = y

  • Simplify

\frac{9x}{3}  -  \frac{15}{3}  = y \\ 3x - 5 = y  \\ y = 3x - 5

From y = mx+b, the slope is 3.

<h3><u>Answer</u></h3>

\large \boxed {slope = 3}

4 0
3 years ago
Ratio 6 to 5 of 20000
neonofarm [45]

Answer:

24000

Step-by-step explanation:

6/5×20000

=24000

4 0
2 years ago
Suppose that, after measuring the duration of many telephone calls, a telephone company found their data was well-approximated b
Musya8 [376]

Answer:

a) 7.79%

b) 67.03%

c) Cumulative Distribution Function

P(t) = \displaystyle\int^{\infty}_{-\infty} 0.1e^{-0.1t}~dt\\\\= \displaystyle\int^{b}_{a} 0.1e^{-0.1t}~dt, ~~a\leq t \leq b

Step-by-step explanation:

We are given the following in the question:

p(x) = 0.1 e^{-0.1x}

where x is the duration of a call, in minutes.

a) P( calls last between 2 and 3 minutes)

=\displaystyle\int^3_2 p(x)~ dx\\\\= \displaystyle\int^3_20.1e^{-0.1x}~dx\\\\=\Big[-e^{-0.1x}\Big]^3_2\\\\=-\Big[e^{-0.3}-e^{-0.2}\Big]\\\\= 0.0779\\=7.79\%

b) P(calls last 4 minutes or more)

=\displaystyle\int^{\infty}_4 p(x)~ dx\\\\= \displaystyle\int^{\infty}_40.1e^{-0.1x}~dx\\\\=\Big[-e^{-0.1x}\Big]^{\infty}_4\\\\=-\Big[e^{\infty}-e^{-0.4}\Big]\\\\=-(0- 0.6703)\\= 0.6703\\=67.03\%

c) cumulative distribution function

P(t) = \displaystyle\int^{\infty}_{-\infty} 0.1e^{-0.1t}~dt\\\\= \displaystyle\int^{b}_{a} 0.1e^{-0.1t}~dt, ~~a\leq t \leq b

6 0
3 years ago
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