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3 years ago

What is the most précis approximation of the square root of 12

Mathematics

2 answers:

igomit [66]3 years ago

5 0

3.46410161514 or 3.5

iogann1982 [59]3 years ago

3 0

The square root of 12 is about 3

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You are part of a school and have to report the results of standardized test scores. Which measure of central tendency would you

USPshnik [31]

You should know this

4 0

3 years ago

The house numbers on the north side of Flynn Street are even. In one block, the house numbers begin 1022, 1032, 1042, and 1052.

never [62]

Answer:

6 houses away

Step-by-step explanation:

You can write down the house numbers and count them:

1032, 1042, 1052, 1062, 1072, 1082

1082 is the 6th house from where Taylor is.

___

You can also recognize that (1082 -1022)/10 = 60/10 = 6 is the number of houses away from the house at 1022.

4 0

3 years ago

A rectangle has an area of 270m2.

Papessa [141]

X * 3 = 270
Solving for x, x = 90

So one side is 90m and the other is 3m.
Now find entire perimeter 90+90+3+3=180+6=186m

8 0

2 years ago

Calculate the average rate of change of the function f(x) = 3x2 over the interval 1 ≤ x ≤ 5.

RideAnS [48]

Answer:

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

here [ a, b ] = [ 1, 5 ]

f(b) = f(5) = 3 × 5² = 75

f(a) = f(1) = 3 × 1² = 3, hence

average rate of change = $\frac{75-3}{5-1}$ = $\frac{72}{4}$ = 18

5 0

3 years ago

P = √mx_ £x MX t make x the subject

vladimir2022 [97]

So, making x subject of the formula, x = [m - 2pt³ ±√(m² - 4pt²m)]/{2t⁵}

<h3>How to make x subject of the formula?</h3>

Since p = √(mx/t) - t²x

So, p + t²x = √(mx/t)

Squaring both sides, we have

(p + t²x)² = [√(mx/t)]²

p² + 2pt²x + t⁴x² = mx/t

Multiplying through by t,we have

(p² + 2pt²x + t⁴x²)t = mx/t × t

p²t + 2pt³x + t⁵x² = mx

p²t + 2pt³x + t⁵x² - mx = 0

t⁵x² + 2pt³x - mx + p²t = 0

t⁵x² + (2pt³ - m)x + p²t = 0

Using the quadratic formula, we find x.

$x = \frac{-b +/-\sqrt{b^{2} - 4ac} }{2a}$

where

a = t⁵,
b = (2pt³ - m) and
c = p²t

Substituting the values of the variables into the equation, we have

$x = \frac{-(2pt^{3} - m) +/-\sqrt{(2pt^{3} - m)^{2} - 4(t^{5})(p^{2}t) } }{2t^{5} }\\= \frac{-(2pt^{3} - m) +/-\sqrt{4p^{2} t^{6} - 4pt^{2}m + m^{2} - 4p^{2}t^{6} } }{2t^{5}}\\= \frac{-(2pt^{3} - m) +/-\sqrt{m^{2} - 4pt^{2}m } }{2t^{5}}\\= \frac{m - 2pt^{3} +/-\sqrt{m^{2} - 4pt^{2}m } }{2t^{5}}$

So, making x subject of the formula, $x = \frac{m - 2pt^{3} +/-\sqrt{m^{2} - 4pt^{2}m } }{2t^{5}}$

Learn more about subject of formula here:

brainly.com/question/25334090

#SPJ1

6 0

1 year ago