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Fantom [35]
3 years ago
12

Emma's grades are 100, 98, 94, 90, and 88. Emma decides not to study for the final because her grades are so high on all of the

previous tests. Emma scores 64 on the final. As an outlier, how does 64 affect the mean of Emma's previous scores? Assume all scores are treated equally.
Mathematics
1 answer:
makkiz [27]3 years ago
8 0

Answer:

Average x = 89

Size n = 6

Sum Sum = 534

Solution:

The Average (Mean) is equal to the Sum of all data divided by the Size of the data set.

Average = Sum / Size

= 534 / 6

= 89

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Papessa [141]

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yes

Step-by-step explanation:

10 × 1/6 < 2

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Square root of 361x^7​
Pavlova-9 [17]

Answer:

19x^3\sqrt{x}

Step-by-step explanation:

19*19=361.

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Write the equation of the line that passes through the points (-9,-4) and (-9,4).
Usimov [2.4K]

Answer:

x = -9

Step-by-step explanation:

x = -9 would be the slope because when you see the two points for each coordinate there is no x value but we do see a straight line and we see that there is no y-intercept. So, x= -9 would be the answer. Hope this helps.

8 0
3 years ago
What is the distance from the origin to point A graphed on the complex plane below?
ExtremeBDS [4]
Distance between two points is
Root of X2 - X1 squared + Y2 - Y1 squared
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5 0
3 years ago
Erik and Caleb were trying to solve the equation: 0=(3x+2)(x-4) Erik said, "The right-hand side is factored, so I'll use the zer
Mumz [18]

Answer:

C) Both

Step-by-step explanation:

The given equation is:

0=(3x+2)(x-4)

To solve the given equation, we can use the Zero Product Property according to which if the product <em>A.B = 0</em>, then either A = 0 OR B = 0.

Using this property:

(3x+2) = 0 \Rightarrow \bold{x = -\frac{2}{3}}\\(x-4) = 0 \Rightarrow \bold{x = 4}

So, Erik's solution strategy would work.

Now, let us discuss about Caleb's solution strategy:

Multiply (3x+2)(x-4) i.e. 3x^2-12x+2x-8 = 3x^2-10x-8

So, the equation becomes:

0=3x^2-10x-8

Comparing this equation to standard quadratic equation:

ax^2+bx+c=0

a = 3, b = -10, c = -8

So, this can be solved using the quadratic formula.

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\dfrac{-(-10)\pm\sqrt{(-10)^2-4\times3 \times (-8)}}{2\times 3}\\x=\dfrac{-(-10)\pm\sqrt{196}}{6}\\x=\dfrac{10\pm14}{6} \\\Rightarrow x= 4, -\dfrac{2}{3}

The answer is same from both the approaches.

So, the correct answer is:

C) Both

3 0
3 years ago
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