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gizmo_the_mogwai [7]
3 years ago
12

A hot air balloon went from an elevation of 4,064 feet to an elevation of 3,322 feet in 28 minutes. What

Mathematics
1 answer:
ELEN [110]3 years ago
3 0

Answer:

<em>The air balloon descends 26.5 feet per minute</em>

Step-by-step explanation:

<u>Rate of Change</u>

The rate of change is a measure that compares two quantities, usually to know how one variable changes in time.

The hot air balloon was 4,064 feet high and, 28 minutes later, it went to 3,322 feet. We can calculate the rate of descent R by dividing the change of elevation over time:

\displaystyle R=\frac{3,322-4,064}{28}=\frac{-742}{28}=-26.5

Thus the air balloon descends 26.5 feet per minute

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mel-nik [20]

Answer:

1. In order to make the integral improper  p  must be 1.

2. In order to make the integral improper  p  must be 1.  

Step-by-step explanation:

Using the rules of integration we get that for

f(x)= \frac{1}{x^p}

\int\limits_{0}^{1}  \frac{1}{x^p}  \, dx  = \frac{x^{1-p}}{(1-p)}  \, |\limits_{0}^{1}   = \frac{1}{1-p} - 0 = \frac{1}{1-p}

Therefore in order to make that integral improper  p  must be 1.

If  p = 1     then you would have a 1/0  indeterminate form.

2.   Using the of integration, specifically substitution we get that for

f(x) = \frac{1}{x(ln(x)^p)}

\int\limits_{e}^{\infty} \frac{1}{x(ln(x))^p} \, dx  = \frac{(ln(x))^{1-p}}{1-p} \, |\limits_{e}^{\infty}

For   p \geq 1  we would have

\int\limits_{e}^{\infty} \frac{1}{x(ln(x))^p} \, dx  = \frac{1}{p-1}

And the problem is the same.  If  p=1   we would have a 1/0 indeterminate form.

5 0
4 years ago
Can someone please help me with this math question?
Phantasy [73]

Answer:

x = (ab - ac )/c

Step-by-step explanation:

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x = (ab - ac )/c.

5 0
3 years ago
What is the slope of a line that is perpendicular to the line y = -1/2 x + 5?
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The only answer that gives this is D:
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8 0
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sattari [20]

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Step-by-step explanation:

Feel pleasure to help u

6 0
3 years ago
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Plz help correct answer gets brainliest.
Leona [35]

whats the question?????

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3 years ago
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