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3 years ago

Explain how a compass works

2 answers:

7 0

A compass has a magnitized needle that follows magnetic fields in the earth to lead you to the South I believe because of how strong the magnetic pull is.

MAVERICK [17]3 years ago

7 0

Answer:

Compasses work so effortlessly because their design allows the magnet to respond freely to Earth's magnetic field. Earth itself is like a giant magnet that creates its own magnetic field. The north end of a compass is drawn to align with Earth's magnetic North Pole

...

A compass points north because all magnets have two poles , a north pole and a south pole, and the north pole of one magnet is attracted to the south pole of another magnet. (You may have seen this demonstrated by a pair of simple bar magnets or refrigerator magnets pushed end to end.)

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Which statements about inertia and centripetal force are correct? Check all that apply. Inertia is always present. Inertia cause

allsm [11]

Inertia IS always present. Inertia is NOT the force that causes objects to continue moving in circles, that is centripetal force. Centripetal force is NOT always present. Centripetal force DOES pull objects toward the center of a circle. <span> Inertia and centripetal force DOES cause circular motion. Thank you and eat sand fren ;)</span>

6 0

3 years ago

Read 2 more answers

A transverse mechanical wave is traveling along a string lying along the x-axis. The displacement of the string as a function of

kvv77 [185]

The wavelength of the wave is 1.16m and the velocity is 23.64m/s.

To find the answer, we have to know more about the Transverse waves.

<h3>How to find different parameters of a wave?</h3>

The displacement of the string as a function of position and time, y(x,t), when the wave traveling along a string lying along the x-axis is given as,

$y(x,t)=0.048sin(5.40x-128t)$

Comparing this with the general form of wave equation, we get,

$amplitude, a=0.048m\\wave vector, k=5.40\\angular frequency,w=128Hz$

We have to find the wavelength of the wave, for this, we have the expression as,

$k=\frac{2\pi }{wavelength} \\\\wavelength=\frac{2\pi }{k} =\frac{2*3.14}{5.40} \\\\wavelength=1.16m$

We have to find the velocity of the wave,

$v=frequency*wavelength\\2\pi f=w, thus,\\f=\frac{w}{2\pi } =\frac{128}{2*3.14}=20.38s^{-1}\\\\v=1.16*20.38=23.64m/s$

Thus, we can conclude that, the wavelength of the wave is 1.16m and the velocity is 23.64m/s

Learn more about the transvers waves here:

brainly.com/question/25746208

#SPJ1

5 0

1 year ago

All of the following activities produce quantitative data exept

Keith_Richards [23]

Answer:

The answer to your question are A and C

Explanation:

Quantitative data are quantities, something that we get after measuring something.

A. Measuring the rate of gas production from a chemical. This example is a quantitative measure, because we are measuring the rate.

B. Describing the clarity of water in a sample If we are describing something, means that we are not measuring anything, so this is not a quantitative measure.

C. Calculating the energy released from an electrochemical reaction If we are not measuring but we are using the data somebody else got to calculate energy, them this is a quantitative data.

7 0

3 years ago

Calculate the specific heat of a metal from the following data. A container made of the metal has a mass of 3.8 kg and contains

OLEGan [10]

Answer:

C = 771.35 J/kg°C

Explanation:

Here, e consider the conservation of energy equation. The conservation of energy principle states that:

Heat Given by Metal Piece = Heat Absorbed by Water + Heat Absorbed by Container

Since,

Heat Given or Absorbed by a material = m C ΔT

Therefore,

m₁CΔT₁ = m₂CΔT₂ + m₃C₃ΔT₃

where,

m₁ = Mass of Metal Piece = 2.3 kg

C = Specific Heat of Metal = ?

ΔT₁ = Change in temperature of metal piece = 165°C - 18°C = 147°C

m₂ = Mass of Metal Container = 3.8 kg

ΔT₂ = Change in temperature of metal piece = 18°C - 15°C = 3°C

m₃ = Mass of Water = 20 kg

C₃ = Specific Heat of Water = 4200 J/kg°C

ΔT₃ = Change in temperature of water = 18°C - 15°C = 3°C

Therefore,

(2.3 kg)(C)(147°C) = (3.8 kg)(C)(3°C) + (20 kg)(4186 J/kg°C)(3°C)

C[(2.3 kg)(147°C) - (3.8 kg)(3°C)] = 252000 J

C = 252000 J/326.7 kg°C

5 0

3 years ago

The symbol used for magnetic field is:

alina1380 [7]

The letter "B" is used for magnetic field

5 0

3 years ago