Kinetic energy = 1/2 * m * V^2
K = 1/2 * 2kg * 4
Explanation:
Fgravity = G*(mass1*mass2)/D²
G is the gravitational constant throughout the universe.
D is the distance between both objects.
D is now reduced by a factor of 5, meaning Dnew = D/5 we get
Fgravitynew = G*(mass1*mass2)/(D/5)² =
= G*(mass1*mass2)/(D²/25) =
= 25* G*(mass1*mass2)/D² = 25* Fgravity
the new force of gravity/attraction is 25×16 = 400 units.
Answer:
τ=0.060 N.m
Explanation:
By kinematics:

Solving for α:

where ωo = 600*2*π/60; ωf = 0; t=10s

The sum of torque is:


