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Gemiola [76]
2 years ago
8

Two students measured the length of their desk each using a different meter stick. One student reported a length of 18 cm and th

e other reported a length of 82cm. What is the most likely explanation for the difference?

Physics
1 answer:
NikAS [45]2 years ago
4 0

The answer to this question is letter C) Each student read the meter stick from different angles.

The students might have been reading the meter stick facing each other. So when one reads the meter stick as 18, the other student will read the reverse image of the measurement. 18 and 82 can be easily mistaken when reversed.

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Which have different numbers of electrons?
nexus9112 [7]

Answer:

isotopes

Explanation:

6 0
3 years ago
If you drop an object from rest, the distance it falls is given by (1/2)at2, where a is the acceleration of the object and t is
klio [65]

If,

d \:  =  \:   \frac{1}{2} a {t}^{2}

then, with 3x time t, (suppose, new distance is h)

h \:  =  \:   \frac{1}{2} a {(3t)}^{2}

=  \frac{1}{2} a9 {t}^{2}

= 9 \:  \frac{1}{2} a{t}^{2}

= 9d

Therefore, new distance h will be 9 times bigger than distance d.

answer: c

7 0
3 years ago
Can someone help me with one through seven I will mark you the brainly
ki77a [65]

Answer:

1.  F = M x A

2. Force  

3. 2nd Law: Force

4. a, b, c (in order)

5. 3rd Law: Action and Reaction

6. b, c, a (in order)

7. 1st Law: Inertia

3 0
2 years ago
Read 2 more answers
An object with a mass of m = 3.85 kg is suspended at rest between the ceiling and the floor by two thin vertical ropes.
Aleksandr-060686 [28]

The tension in the upper rope is determined as 50.53 N.

<h3>Tension in the upper rope</h3>

The tension in the upper rope is calculated as follows;

T(u) = T(d)+ mg

where;

  • T(u) is tension in upper rope
  • T(d) is tension in lower rope

T(u) = 12.8 N + 3.85(9.8)

T(u) = 50.53 N

Thus, the tension in the upper rope is determined as 50.53 N.

Learn more about tension here: brainly.com/question/918617

#SPJ1

6 0
2 years ago
Two charged particles separated by a distance of = 3 and experienced electrostatic forces of = 60 . What would be this force if
klemol [59]

Answer: 539.4 N

Explanation:

Let's begin by explaining that Coulomb's Law establishes the following:  

"The electrostatic force F_{E} between two point charges q_{1} and q_{2} is proportional to the product of the charges and inversely proportional to the square of the distance d that separates them, and has the direction of the line that joins them"

What is written above is expressed mathematically as follows:

F_{E}= K\frac{q_{1}.q_{2}}{d^{2}} (1)

Where:

F_{E}=60 N  is the electrostatic force

K=8.99(10)^{9} Nm^{2}/C^{2} is the Coulomb's constant  

q_{1} and q_{2} are the electric charges

d=3 m is the separation distance between the charges  

Then:

60 N= 8.99(10)^{9} Nm^{2}/C^{2}\frac{q_{1}.q_{2}}{(3 m)^{2}} (2)

Isolating q_{1} and q_{2}:

q_{1}q_{2}=6(10)^{-8} C^{2} (3)

Now, if we keep the same charges but we decrease the distance to d_{1}=1 m, (1) is rewritten as:

F_{E}=8.99(10)^{9} Nm^{2}/C^{2}\frac{6(10)^{-8} C^{2}}{(1 m)^{2}} (4)

Then, the new electrostatic force will be:

F_{E}= 539.4 N (5) As we can see, the electrostatic force is increased when we decrease the distance between the charges.

4 0
2 years ago
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