Question

A brick walkway forms the diagonal of a square playground. The walkway is 20 m long. To the nearest tenth of a meter, how long is one side of the playground?

Answer 1

Answer: 14 meters

Step-by-step explanation:

The equation will be:

x^2 + x^2 = 20^2

Add x^2

2x^2=400

Divide both side by 2

x^2 = 400/2

x^2 = 200

Square both side

x = sqrt(200)

x = 14 meters

So each side has 14 meters

Answer 2

Answer:

length of one side of the play ground is $x=14 \ meters$ .

Step-by-step explanation:

Given:

Ground is a squared shape

diagonal of the square is = 20m

Required:

Length of one side of the playground=$x=?$

Solution:

As we know that in square all sides are of equal length so let the length of one side of a square is $x$.

The diagonal of a square divides the square into two 45-45-90 triangles.

in 45-45-90 triangle the sides are $x, x, \ and \ x\sqrt{2}$ as shown in the figure (attached below)

$x\sqrt{2}$ is the diagonal of the square so $x\sqrt{2}=20\\x=\frac{20}{\sqrt{20} }\\ x=10\sqrt{2} \ OR \ 14.142$

so the length of one side of the ground is $x=14.142\ meters$

rounding the answer to nearest tenth of a meter, we get

$x=14 \ meters$