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natulia [17]
3 years ago
7

WILL MARK BRAINLIEST IF RIGHT NEED IT ASAP Evaluate the expression for j = 5. 2j^2 =

Mathematics
2 answers:
postnew [5]3 years ago
8 0

Answer: 50

Step-by-step explanation:

To evaluate the expression, you want to plug j into the expression and solve.

2(5)²               [exponent]

2(25)             [multiply]

50

After plugging in j=5, we found that the expression is equal to 50.

lisov135 [29]3 years ago
4 0

Answer:

50

Step-by-step explanation:

your expression: 2j²

plug in j = 5: 2(5)²

solve for the exponent: 2(25)

multiply: 50

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You want to solve 11% of what number is 22. Explain how you can solve that by using a proportion
Doss [256]
Write the first ratio as 11/100 and set it equal to 22/n.

since 11 x 2=22 you can multiply 100 x 2 and you'll get 200. 

*Check*: 11% of 200=22
3 0
2 years ago
What is 8c + 10b ÷ 7a if c = 7, b = 12, and a = 5 Please give a full and good explanation for a brainliest...​
PolarNik [594]

Answer:

141  5/7

Step-by-step explanation:

8c + 10b ÷ 7a

Let c = 7, b = 12, and a = 5

8*7 + 10*12 ÷ 7*5

Multiply and divide from left to right

56+120 ÷7*5

56+ 600/7

Get a common denominator

392/7 + 600/7

992/7

Change from an improper fraction to a mixed number

141  5/7

8 0
2 years ago
Read 2 more answers
Curt and Ian both ran a mile. Curt time was 8/9 of Ian time. Who ran faster?
Leona [35]

Curt because if his time was 8/9 of Ian's time then that means he ran the mile in a fraction of Ian's time, so he finished the mile quicker. Curt ran faster.

5 0
3 years ago
Read 2 more answers
What is the answer to number 23
attashe74 [19]

The answer is 50/27 or 1 23/27 or approx 1.85185. Here is my work!

Multiply both sides by 10 : 20x + 6x = 50 - x

Collect the like terms: 20x + 6x = 50 - x

Move Variable to Left: 26x + x = 50

Collect like terms: 27x = 50

Divide both sides by 27: 50/27

Hope this helped :))

6 0
2 years ago
One number is 6 more than anouther number. the sum of their squares is 90
Flura [38]
Let x = greater number
      y = smaller  number

(1) x = y + 6

(1) y = x-6

(2) x^{2} + y^{2} = 90
We'll substitute y in (1) to (2)
(2) x^{2} +  (x-6)^{2} = 90
     x^{2} +  (x^{2} - 12x + 36) = 90
     x^2 + x^2 -12x + 36 - 90 = 0
     2x^2 - 12x -54 = 0

     2(x^2 - 6x - 27) = 0
     2(x - 9)(x + 3) = 0
 x - 9 = 0        or      x + 3 = 0
      x = 9                        x = -3
and
 y = x - 6                  y = x - 6
 y = 9 - 6                  y = -3 - 6
 y = 3                        y = -9

Therefore, the two numbers can be 9 and 3 or -3 and -9.

      
6 0
3 years ago
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