All categories

3 years ago

WILL MARK BRAINLIEST IF RIGHT NEED IT ASAP Evaluate the expression for j = 5. 2j^2 =

Mathematics

2 answers:

postnew [5]3 years ago

8 0

Answer: 50

Step-by-step explanation:

To evaluate the expression, you want to plug j into the expression and solve.

2(5)² [exponent]

2(25) [multiply]

After plugging in j=5, we found that the expression is equal to 50.

lisov135 [29]3 years ago

4 0

Answer:

Step-by-step explanation:

your expression: 2j²

plug in j = 5: 2(5)²

solve for the exponent: 2(25)

multiply: 50

You might be interested in

A teacher is making multiple copies of a 1−page homework assignment. The time it takes her in seconds based on the number of cop

avanturin [10]

Answer: I'm on it give me just a minute!!

6 0

2 years ago

What is the next number in the sequence 3, 12, 24, 33, 66

ExtremeBDS [4]

75.
Explanation: from 3 to 12, you add 9, and then double the 12 to get to 24, and then add 9 again to get to 33, and double it to get 66, so the pattern is to add 9 and then double.

4 0

3 years ago

Read 2 more answers

What is the balance on a deposit of $1,150 that earns 9% interest compounded annually for 2 years

igor_vitrenko [27]

Step One: Calculate interest.

$1150*0.09=103.5$

Step Two: Calculate the amount at the end of the first year.

$1150+103.5=1253.5$

Step Three: Calculate the amount at the end of the second year. This will be your final answer.

$1253.5+103.5=1357$

$1357 balance

3 0

3 years ago

The ages of people on the camp bus are listed. 10, 15, 14, 8, 18, 11, 12, 12, 10, 10, 17, 16 What is the mode of the ages?

oksian1 [2.3K]

Mode is the number that mostly occurs so its a.10

3 0

3 years ago

Read 2 more answers

Evaluate the following double integral where a = 2y

Keith_Richards [23]

Change the order of integration.

$\displaystyle \int_0^1 \int_{2y}^2 \cos(x^2) \, dx \, dy = \int_0^2 \int_0^{x/2} \cos(x^2) \, dy \, dx \\\\ ~~~~~~~~ = \int_0^2 \cos(x^2) y \bigg|_{y=0}^{y=x/2} \, dx \\\\ ~~~~~~~~ = \frac12 \int_0^2 x \cos(x^2) \, dx$

Substitute $u=x^2$ and $du=2x\,dx$ .

$\displaystyle \frac12 \int_0^2 x \cos(x^2) \, dx = \frac14 \int_0^4 \cos(u) \, du = \frac14 \sin(u) \bigg|_{u=0}^{u=4} = \boxed{\frac{\sin(4)}4}$

4 0

10 months ago