Answer:
We could get the time taken by the ball to return back to earth, using the formula:
s = u t + ½ a t², where
s = displacement of the body moving with initial velocity u, acceleration 'a' in time t.
In the present case s=0 (as the ball returns back to starting time)
u= 30 m/s; a = -10 m/s² ( negative sign as a is in opposite direction to u); t=?
0 = 30 t - ½ ×10 ×t²; ==> 5 t = 30, t= 6 second.
So ball will return back after 6 second after being thrown up.
Explanation:
I looked it up
Hope this helps
Answer:
Explanation:
The formula for velocity is:
Where
is the ball's initial velocity.
solving for a:
The magnitude of the current in wire 3 is (I₃)= 0.33A
<h3>How to calculate the value of the magnitude of the current in wire 3 ?</h3>
To calculate the magnitude of the current in wire 3 we are using the Kirchhoff’s current law,
I₁ + I₂ + I₃ = 0
Where we are given,
I₁ = current in wire 1
=0.40 A.
I₂ = current in wire 2
= -0.73 A.
We have to calculate the magnitude of the current in wire 3, I₃
Now we put the known values in above equation, we get,
I₁ + I₂ + I₃ = 0
Or, I₃ = -.(I₁ + I₂)
Or, I₃ = -.(0.40 - 0.73)
Or, I₃ = 0.33 A
From the above calculation, we can conclude that the current in wire 3 is I₃ = 0.33 A
Learn more about current:
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Answer: b) one-third as great.
Explanation:
The options include:
a) three times greater.
b) one-third as great.
c) half as great.
d) two times greater.
e) the same.
Since the water heats up to 40°C and the room temperature is about 20°C before the start of the experiment, heat absorbed will be: (40°C-20°C).= 20°C
Since mystery metal heats up to 80∘C and the room temperature is about 20°C before the start of the experiment, heat absorbed will be: (80°C-20°C).= 60°C.
Therefore, based on the calculation, when compared to that of water, the heat capacity of our mystery metal is (20/60) = 1/3 one-third as great.
