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egoroff_w [7]
3 years ago
12

A sled is moving down a steep hill. The mass of the sled is 50 kg and the net force acting on it is 20 N. What must be done to f

ind the acceleration of the sled? Which ones apply to this scenario.
1. The force of gravity must be broken into its parallel and perpendicular components.

2. Acceleration can be found by dividing the net force by mass.

3. Acceleration can be found by multiplying the net force by mass.

4. The magnitude of the force components must be multiplied by gravity.

5. Trigonometry can be used to solve for the magnitude of the force components.

6. Net force must be found before acceleration can be found.
Physics
2 answers:
yKpoI14uk [10]3 years ago
5 0
Number 4 is the right answer
Rashid [163]3 years ago
4 0
I believe the answer is #4. u can always ask google if u believe that's the wrong answer :)
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The atmosphere of earth does not escape into the space but remains attached to earth's surface why??
Alexeev081 [22]

Just like any other gas or mixture of gases, the gas molecules are
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different speeds. 

Those that happen to be moving at a speed greater than the Earth's
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any other molecules before they escape, are lost.

With the combination of Earth's escape velocity, and the temperatures,
thickness, and density of the atmosphere, that process happens slowly
enough to have maintained an atmosphere around this planet until now.

Personally, I hope it hangs around for a while longer.  But with the constant
increase in temperature that's been going on, you never know . . .

7 0
3 years ago
A conductor of radius r, length and resistivity ρ has resistance r. what is the new resistance if it is stretched to 4 times its
max2010maxim [7]
The resistance of a conductor is given by
R= \frac{\rho L}{A}
where L is the length of the wire, \rho the resistivity of the material and A the cross-sectional area.

We can see that if all the other quantities do not change, if the new length of the conductor is 4 times the original length: L'=4 L, then the new resistance is also 4 times the original value:
R'= \frac{\rho L'}{A}= \frac{\rho 4 L}{A}=4  \frac{\rho L}{A}=4 R
7 0
3 years ago
A point on the string of a violin moves up and down in simple harmonic motion with an amplitude of 1.24 mm and frequency of 875
mario62 [17]

Using

V = Amplitude x angular frequency(omega)

But omega= 2πf

= 2πx875

=5498.5rad/s

So v= 1.25mm x 5498.5

= 6.82m/s

B. .Acceleration is omega² x radius= 104ms²

5 0
3 years ago
Read 2 more answers
A snail and an inchworm are in a race. Their race track heads north for a distance of 2 m. If the inchworm comes to the end of t
olga2289 [7]
Well the basic equation for velocity is v=d/t where d is distance and t is time. So v=2m/50s and the answer is v=0.04meter/second.
7 0
3 years ago
Karen has a mass of 51.9 kg as she rides the up escalator at Woodley Park Station of the Washington D.C. Metro. Karen rode a dis
kifflom [539]

Answer:

28852 J

Explanation:

When a force applied in a body produces a displacement in it, the force realized a work. The force that moves Karen is contrary to her weight and must be equal to it.

The work (W) is:

W = F.d.cos(θ), where F is the force, d is the displacement, and θ is the angle.

Knowing that cos(26°) = 0.899, and F = m*g

W = 51.9*9.8*63.1*0.899

W = 28852 J

4 0
3 years ago
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