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3 years ago

12

A sled is moving down a steep hill. The mass of the sled is 50 kg and the net force acting on it is 20 N. What must be done to f

ind the acceleration of the sled? Which ones apply to this scenario.
1. The force of gravity must be broken into its parallel and perpendicular components.

2. Acceleration can be found by dividing the net force by mass.

3. Acceleration can be found by multiplying the net force by mass.

4. The magnitude of the force components must be multiplied by gravity.

5. Trigonometry can be used to solve for the magnitude of the force components.

6. Net force must be found before acceleration can be found.

2 answers:

yKpoI14uk [10]3 years ago

5 0

Number 4 is the right answer

Rashid [163]3 years ago

4 0

I believe the answer is #4. u can always ask google if u believe that's the wrong answer :)

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How can a model be created to predict how forces affect objects at a distance?

olchik [2.2K]

Answer:

Gravitational force increases as the masses of the objects increase and decreases as the distance between the objects increases. Balanced forces acting on an object cause no change in the motion of the object. When unbalanced forces act on an object, the sum of the forces is not equal to zero.

Explanation:

put it in your own words

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3 years ago

What should be the indication on the magnetic compass as you roll into a standard rate turn to the right from a northerly headin

lapo4ka [179]

Answer:

The compass will indicate a turn to the left.

Explanation:

The magnetic compass has a needle pointing towards north. It is used for navigation and it shows direction with respect to the geographical cardinal direction.

As we move to the right of the northerly heading in northern Hemisphere, the direction of needle will move towards left but with a faster rate as now the direction of north is no his left.

This shows the compass if following its direction properly.

4 0

3 years ago

Visible light passes through a diffraction grating that has 900 slits per centimeter, and the interference pattern is observed o

kobusy [5.1K]

Answer:

$\Delta \lambda=14.3\ nm$

Explanation:

It is given that,

The number of lines per unit length, N = 900 slits per cm

Distance between the formed pattern and the grating, l = 2.3 m

n the first-order spectrum, maxima for two different wavelengths are separated on the screen by 2.98 mm, $\Delta Y=2.98\ mm = 0.00298\ m$

Let d is the slit width of the grating,

$d=\dfrac{1}{N}$

$d=\dfrac{1}{900\ cm}$

$d=1.11\times 10^{-5}\ m$

For the first wavelength, the position of maxima is given by :

$y_1=\dfrac{L\lambda_1}{d}$

For the other wavelength, the position of maxima is given by :

$y_2=\dfrac{L\lambda_2}{d}$

So,

$\Delta \lambda=\dfrac{\Delta y d}{l}$

$\Delta \lambda=\dfrac{0.00298\times 1.11\times 10^{-5}}{2.3}$

$\Delta \lambda=1.43\times 10^{-8}\ m$

or

$\Delta \lambda=14.3\ nm$

So, the difference between these wavelengths is 14.3 nm. Hence, this is the required solution.

3 0

3 years ago

3. Calculate the wavelength of wave that has a frequency of 4.75 x 1012Hz.

Klio2033 [76]

Frequency=v=4.75×10^12Hz
Wavelength=?

We know

$\boxed{\sf \lambda=\dfrac{C}{V}}$

$\\ \sf\longmapsto \lambda=\dfrac{3\times 10^8ms^{-1}}{4.75\times 10^{12}s^{-1}}$

$\\ \sf\longmapsto \lambda=0.631\times 10^{-4}m$

$\\ \sf\longmapsto \lambda=6.31\times 10^{-5}m$

4 0

3 years ago

IP The x and y components of a vector r⃗ are rx = 16 m and ry = -8.5 m , respectively

fiasKO [112]

as it is given that

$r_x = 16 m$

$r_y = -8.5 m$

now we will have

$\vec r = 16 \hat i - 8.5 \hat j$

now the magnitude of this vector is given as

$|r| = \sqrt{16^2 + 8.5^2}$

$|r| = 18 m$

now to find the direction we can use

$tan\theta = \frac{r_y}{r_x}$

$tan\theta = \frac{-8.5}{16}$

$\theta = tan^{-1}(-0.53)$

$\theta = - 28^0$

4 0

4 years ago