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mojhsa [17]
3 years ago
8

NEED HELP FOR EXAMS ASAP

Physics
2 answers:
Delvig [45]3 years ago
7 0

B)reference level from which the height is measured.

PIT_PIT [208]3 years ago
7 0

B)reference level from which the height is measured.

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An 80 kg object has a µk = 0.35 and a µs = 0.60. Assuming it is on a flat surface
Over [174]

Answer:

What is the normal force on the object (draw a diagram if needed)

784 N

How much force is required to get the object to start to move from rest (max static friction)?

  470.4 N

When the object starts moving, what is the force of kinetic friction?

274.4 N

If the moving object has a tension force of 300N to the right pulling it, what is the net force on the object in the horizontal direction? 784 N

What is the acceleration (with direction) of the object based on your answer for part d?  Remember that a = net force/m.

Explanation:

6 0
3 years ago
What is the voltage in a circuit if the current is 6 Amps and resistance is 6 ohms
Mrrafil [7]

U=R•I=6•6=36 V

............

3 0
4 years ago
What angle is formed by the sun, the earth, and the moon during an eclipse?.
Andrew [12]

Answer:

The Sun-Earth-Moon system happens to exhibit a striking geometric coincidence, which we examine in the first problem. PROBLEM 1. To an observer on Earth, the Sun and the Moon subtend almost the same angle in the sky. The average angle is 0.52 degrees for the Moon and 0.53 degrees for the Sun.

4 0
3 years ago
In 1996, astronomers discovered an icy object beyond pluto that was given the designation 1996 tl 66. it has a semimajor axis of
antoniya [11.8K]

Answer : 2446 years.

Explanation :

Length of semi major axis is, a=84\ au= 1.496\times 10^{11}\ m

According to Kepler's third law, square of time period of an orbit is directly proportional to the cube of the semi major axis.

i.e T^2=\dfrac{4\pi^2}{GM}a^3

where G is gravitational constant

M is  mass of sun, M=1.98\times 10^{30}\ Kg

So, T^2=\dfrac{4\times (3.14)^2}{6.6\times 10^{-11}Nm^2/Kg\times 1.98\times 10^{30}\Kg}

T^2=3\times 10^{-19}\times(84\times 1.496\times 10^{11})^3

T^2=3\times 10^{-19}\times 1984415.6\times 10^{33}

T^2=59532469.8\times 10^{14}\ s

T=7715.7\times 10^7\ s

since, 1\ sec=3.17\times 10^{-8}\ years

So, orbital period is approximately 2446 years.

7 0
4 years ago
Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t
bekas [8.4K]

Answer:

0.13 m/s

Explanation:

m_1 = Mass of first car = 140000 kg

m_2 = Mass of second car = 95000 kg

u_1 = Initial Velocity of first car = 0.3 m/s

u_2 = Initial Velocity of second car = -0.12 m/s

v = Velocity of combined mass

For elastic collision

m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow  v=\frac{140000\times 0.3 + 95000\times -0.12}{140000+ 95000}\\\Rightarrow v=0.13\ m/s

Their final velocity is 0.13 m/s

6 0
3 years ago
Read 2 more answers
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