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3 years ago

1. Consider the rational numbers 4/13 and 3/10.

1 answer:

5 0

A)4/13 would be the larger number since if you were to try to add them, 4/13 = 40/130 and 3/10 = 39/130, 40/130 > 39/130

B) A rational number between them would be 39.5/130.

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Which is the graph for f(x)=3 tothepowerof x? Pls just say the letter, no pictures. I can't see them. For 20 points.

Dafna1 [17]

The answer is D. Trust me

4 0

3 years ago

Solve for the coefficient -5=a(0-2)(0-3)(0-5)

Sonja [21]

Answer:

a = 1/6

Step-by-step explanation:

-5=a(0-2)(0-3)(0-5)

Simplify

-5=a(-2)(-3)(-5)

-5 = a(-30)

Divide each side by -30

-5/-30 = -30a/-30

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3 years ago

Let f(x) = 13 - |2x+ 1|. Find all x for which f(x) less than or equal to 14

Art [367]

Answer:

$x \leqslant -1\: or \: x \geqslant - 1$

Step-by-step explanation:

The given function is

$f(x) = 13 - |2x + 1|$

We want to find all values of x for which:

f(x) is greater than or equal to 14.

This implies;

$13 - |2x + 1| \geqslant 14$

Subtract 13 from both sides;

$- |2x + 1| \geqslant 14 - 13$

$|2x + 1| \geqslant - 1$

By definition of the absolute value function,

$- (2x + 1) \geqslant - 1 \: or \: (2x + 1) \geqslant - 1$

Divide through the first inequality and and reverse the inequality sign:

$2x + 1 \leqslant -1 \: or \: 2x + 1 \geqslant - 1$

$2x \leqslant -1 - 1 \: or \: 2x \geqslant - 1 - 1$

$2x \leqslant -2 \: or \: 2x \geqslant - 2$

$x \leqslant -1\: or \: x \geqslant - 1$

8 0

4 years ago

Solve for area of the shaded region (#61) <br> Pls explain im so confused

BartSMP [9]

Answer: So after reading my explanation you can simply find the area good luck!

Step-by-step explanation:

Inequality 1 is graphed in blue and inequality 2 is graphed in red. The overlap of the shaded regions (purple shading) represents the solution. ... Inequality 1 is graphed in blue and inequality 2 is graphed in red. In this case the regions do not overlap. This indicates that there is no solution to the system