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-BARSIC- [3]
3 years ago
12

The wind speed s (in miles per hour) is related to the distance (in miles) the tornado travels by the equation s = 93log d + 65.

On March 18, 1925, a tornado whose wind speed was about 280 miles per hour struck the Midwest. How far did the tornado travel?
Mathematics
1 answer:
Vesnalui [34]3 years ago
7 0

Answer:

The distance the tornado traveled was approximately 205 miles.

Step-by-step explanation:

The equation representing the relationship between the wind speed (in miles per hour) and the distance the tornado travels (in miles) is:

s=93\log d+65

Compute the value of <em>d</em> for <em>s</em> = 280 as follows:

        s=93\log d+65

     280=93\log d+65

93\log d=280-65\\93\log d=215

   \log d=2.312\\

        d=10^{2.312}\\d=205.035\\d\approx 205

Thus, the distance the tornado traveled was approximately 205 miles.

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<h2>¡Hola!</h2>

La multiplicación de las fracciones es 2/3

Para multiplicar las dos fracciones tenemos que multiplicar en línea: numerador por numerador y denominador por denominador.

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: {\sf \rightarrow  \dfrac{12}{15} \times  \dfrac{5}{6} }

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\:  \:  \:  {\sf \rightarrow\dfrac{12}{15}\times \dfrac{5}{6}=\dfrac{12 \times 5}{15 \times 6}=\dfrac{60}{90} =\dfrac{2}{3} }

Por lo tanto, la multiplicación de las fracciones es 2/3

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