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enot [183]
3 years ago
11

A free electron and a free proton are released in identical electric fields.

Physics
1 answer:
notka56 [123]3 years ago
4 0

Answer:

i) They are equal . ii) It is thousands of times greater for the electron.

Explanation:

i) By definition, the electric field is the electric force per unit charge. If the field is the same, the force will depend on the value of the charge under the influence of the field.

As the magnitude of  the charge of the electron and the proton are the same, we conclude that the electric force on both must be equal in magnitude.

ii) The acceleration on both particles must meet the Newton´s 2nd Law, so, if the forces are equal in magnitude (neglecting any other external interaction), the acceleration will only depend on the mass of both particles, according this general expression:

a = F/m

As the mass of the electron is approximately two thousands times smaller than the proton´s, it concludes that the acceleration on the electron must be thousands of times greater for the electron.

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NEED HELP NOW. I WILL BRAINLIEST
NeTakaya

Answer:

number of Protons=16

number of Neutrons=16

number of electrons=32

Explanation:

Tip:-

<em><u>Always the number of protons = the number of neutrons.</u></em>

<em><u>Add them and you will get the number of electrons.</u></em>

<u><em>Happy to help</em></u>

ADD ME BRAINLIEST AS YOU SAID

YOUR WELCOME

3 0
3 years ago
An electron moving with a velocity v⃗ = 5.0 × 107 m/s i^ enters a region of space where perpendicular electric and a magnetic fi
stiv31 [10]

Answer:

Magnetic field, B=2\times 10^{-4}\ T

Explanation:

Given that,

Velocity of electron, v=5\times 10^7\ m/s

It enters  a region of space where perpendicular electric and a magnetic fields are present.

Magnitude of electric field, E=10^4\ V/m

We need to find the magnetic field will allow the electron to go through the region without being deflected.

Magnetic force on the electron, F_m=qvB\ sin\theta.......(1)

Electric force on the electron, F = q E........(2)

From equation (1) and (2) we get:

qvB\ sin\theta=qE

B=\dfrac{E}{v}

B=\dfrac{10^4\ V/m}{5\times 10^7\ m/s}

B = 0.0002 T

or

B=2\times 10^{-4}\ T

Hence, this is the required solution.

3 0
3 years ago
How long will it take, in minutes, for a transformer to transfer 2.3 X 10^6 J of energy from a 120-V circuit to a 345-V circuit
masya89 [10]

Answer:

e

Explanation:

3 0
3 years ago
PLEASE HELP! Daniel is 50.0 meters away from a building. He observes that his line-of-sight to the tip of the building makes an
zavuch27 [327]

Answer:

The height of building should be 98.13 m plus the height of Daniel. Since the 63° was measured from his eye level.

Explanation:

5 0
3 years ago
What is the acceleration of an object with a constant velocity
valina [46]

Zero.

Acceleration is defined as the change in velocity over time.

Since in your case there is no change, there is no acceleration, so it is zero:

Or in formula: <span>a=<span><span>Δv</span>t</span></span>

Where a=acceleration, <span>Δv</span>=change in velocity and t=time

6 0
3 years ago
Read 2 more answers
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