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TiliK225 [7]
3 years ago
6

An object with a mass of 1500 g (grams) accelerates 10.0 m/s2 when an

Physics
2 answers:
masya89 [10]3 years ago
8 0

Answer:

15N

Explanation:

F=ma

m=1500g = 1.5kg

a=10m/s2

1.5×10=15 N

Mila [183]3 years ago
7 0

Answer:15000gms^-2

Explanation:

F=m×a

m=1500g, a=10ms^-2

F=(1500×10)gms^-2

F=15000gms^-2

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Let F1=Force exerted by the brother (+F1)
F1= Force exerted by the sister (-F2)

Fnet=(+F1) + (-F2)
Fnet= (+F1) + (-F2)
Fnet=F1 - F2
Fnet= (+3N)+(-5N)
Fnet= -2N

-F

towards the sister (-F) (greater force applied)
7 0
3 years ago
Atoms can join together to form ______ substance​
ELEN [110]

Answer:

Molecules

Explanation:

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3 years ago
An object that completes 20 vibrations in 10 seconds has a frequency of
nika2105 [10]

Answer:

<em> The object has frequency of 2 Hz and time period of 0.5 s.</em>

Explanation:

<em>Frequency</em> is defined as number of oscillation per second ie back and forth swings done in single second.

Here it is given that the object oscillates 20 times in 10 seconds.

So f = \frac{20}{10} = 2Hz

The <em>time period</em> is defined as time taken by the object to complete one full oscillation.

T = \frac{1}{f}

T= \frac{1}{2} =0.5 s

<em>Thus the object has frequency of 2 Hz and time period of 0.5 s.</em>

7 0
3 years ago
Decide which of the following day-to-day activities might be considered aerobic exercise?
erastova [34]

Answer:

3. Mowing the lawn

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Aerobic exercise is any type of cardiovascular conditioning.

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3 0
3 years ago
Read 2 more answers
An 56 kg sled is being pulled across the snow, at constant speed,by a horizontal force of 15 N, find the coefficient of kinetic
Stolb23 [73]

Answer:

The coefficient of  kinetic friction = 0.026  

Explanation:

An 56 kg sled is being pulled across the snow, at constant speed,by a horizontal force of 15 N.

Here we have to note that the weight is pulled at a constant speed . This means that the net force acting on the weight is zero.

The external force acting on the body is in the forward direction and the friction acts in the backward direction.

Friction increases as the mass of the body increases.

Friction = u_{k}\times m \times g

We now equate this to the external force of 15 N.

15 = u_{k} \times 56 \times 10

u_{k} = \frac{15}{560}

u_{k} = 0.026

The coefficient of  kinetic friction = 0.026  

8 0
3 years ago
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