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BlackZzzverrR [31]
3 years ago
11

You might think that an ultraviolet light shining on an initially uncharged electroscope would cause the electroscope to become

positively charged as photoelectrons are emitted. In fact, ultraviolet light has no noticeable effect on an uncharged electroscope. Why not
Physics
1 answer:
xeze [42]3 years ago
6 0

Answer:

Positively Charge formation on the electroscope pulls the electrons so no emission happens.

Explanation:

Photoelectric effect is the process by which the electrons get ejected when light of certain frequency falls on the material. The energy from the electromagnetic radiation excites the electron by providing it enough energy as a result it gets ejected.

The Ultraviolet(UV) light is a form of electromagnetic radiation, If the UV radiation strikes an uncharged electroscope, it is predicted that it will cause the electrons in the electroscope to excite and to be emitted.  But on the contrary no noticeable effect is observed on the electroscope this happened because when UV light makes the electroscope positively(+) charged this creates a pull for the electrons, as a result rather emitting the electrons gets pulled by the positively charged electroscope.

Therefore the positively charge formation on the electroscope hinder the electrons emission and there is no noticeable effect.  

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An object has a mass of 14 grams and a density of 7 g/mL. When placed in water it sinks. What is the Volume of water displaced?
iVinArrow [24]

Explanation:

D = M/V

We rearrange this equation to get V = M/D

So 14 g/7 g/mL,

the grams cancel out, and we're left with 2 mL.

D is the answer.

3 0
4 years ago
Tom and Mary are riding a merry-go-round. Tom is on a horse about half way between the center and the outer rim, and Mary is on
iren2701 [21]

Answer:

Explanation:

Given

Tom is on half way between the center and the outer rim

Mary is on the extreme outer rim

Suppose \omega is the angular velocity of ride with radius of outer rim be R

\alpha =angular acceleration of Ride

At any instant both Tom and Mary experience the same angular speed

(b)Linear velocity at any instant

v_{Tom}=\omega \times R

v_{Mary}=\omeag \times \frac{R}{2}

Thus Tom has higher linear speed

(c) For radial Acceleration

a_r=\omega ^2\times r

a_{Tom}=\omega ^2\times R

a_{Mary}=\omega ^2\times \frac{R}{2}

Tom has higher radial Acceleration as it is directly Proportional of radius          

7 0
3 years ago
Which statement best compares potential and kinetic energy?. .
Pachacha [2.7K]
The statement that best compares potential and kinetic energy would be : B. only kinetic energy increases when velocity of an object increases

Formula in calculating kinetic energy is : 1/2 m v^2.
which mean as velocity increased, the kinetic energy would be larger

hope this helps
5 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!!!!
Damm [24]

I believe the answer is resonance

6 0
3 years ago
I'll give the brainliest!
Vaselesa [24]

Answer:

Explanation:

1. Althea Gibson

2. Nathon Green

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4 conused

5.Norm Duke- At 18

          Hope this helps!!

8 0
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