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Mila [183]
3 years ago
11

Which transformations were used to create A’B’C’?

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer:

the anser is 3.


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What is -5 5/8 + 3 1/2
aksik [14]

Answer:

exact form: -17/8

decimal form: -2.125

mixed number form: -2 1/8

Step-by-step explanation:

cmon this is freaking addition

4 0
2 years ago
F(x)=-3/5x+k and if f(30)=-11 what is the value of k
Kruka [31]

Answer:

k=20.

Explanation: First we find where f(x) has its local extrema: f'(x)=3x2−10x+3. The critical points are roots of the equation: 3x2−10x+3=0.

6 0
3 years ago
Sonja's house is 4 blocks west and 1 block south of the center of town. Her school is 3 blocks east and 2 blocks north of the ce
dexar [7]

If the center of town is the origin then 4 blocks west and 1 block south would be 4 blocks to the left and 1 block down or (-4, -1) house 3 block east and 2 blocks north would be 3 blocks to the right and 2 blocks up or (3, 2) use the distance formula to find the distance between two points. That's all I know! hope this helps!~ just remember to use the distance formula to find the distance between two points.

5 0
3 years ago
Read 2 more answers
Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball
Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and 51\frac{1}{3} yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from 51\frac{1}{3} yards.

\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}

Let us have a common denominator.

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}  

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}

\text{1 yard}=3\text{ feet}

\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}

\frac{28}{3}\text{ yards}=28\text{ feet}

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

7 0
3 years ago
Harold, a marina manager, purchased two boats. He then sold the boats, the first
zaharov [31]

Harold paid $ 16,632 and $ 38,808 for each of the boats.

Since Harold, a marina manager, purchased two boats, and he then sold the boats, the first at a profit of 40% and the second at a profit of 60%, and the total profit on the sale of the two boats was 54 % and $ 88 704 was the total selling price of the two boat, to determine what did Harold originally pay for each of the two boats the following calculation must be performed:

  • 55 x 0.6 + 45 x 0.4 = 51
  • 65 x 0.6 + 35 x 0.4 = 53
  • 70 x 0.6 + 35 x 0.4 = 54

  • 88,704 x 0.7 = 62,092.80
  • 160 = 62,092.80
  • 100 = X
  • 100 x 62,092.80 / 160 = X
  • 38.808 = X

  • 88,704 x 0.3 = 26,611.20
  • 140 = 26,611.20
  • 100 = X
  • 100 x 26,611.20 / 160 = X
  • 16,632 = X

Therefore, Harold paid $ 16,632 and $ 38,808 for each of the boats.

Learn more in brainly.com/question/21446500

7 0
3 years ago
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