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marissa [1.9K]
3 years ago
5

The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain?

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
3 0
{k^2 + 2k + 1 = 25, k^2 + 2k + 1 = 64}
{k^2 + 2k - 24 = 0, k^2 + 2k - 63 = 0}
{(k - 4)(k + 6) = 0, (k - 7)(k + 9) = 0}
{k = -6, 4, -9, 7)
Therefore, range = {-9, -6, 4, 7)
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makkiz [27]

Answer:

Step-by-step explanation:

They are equivalent.  Use the distributive property.

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the 3 on the outside of the parenthesis is multiplied by the variable(the letter) and thenthe constant(number) inside the parenthesis.

makes and equivalent equation 3x+9

5 0
3 years ago
is it possible to have a right triangle in which the sine of one of the angles is equal to the cosine of one of the angles? why?
stira [4]

Answer:

Yes , it is possible (see the explanation)

Step-by-step explanation:

we know that

In a right triangle, we have two complementary angles (their sum equal to 90 degrees)

so

If two angles are complementary, the cofunction identities state that the sine of one equals the cosine of the other and vice versa

<em>Example</em>

Suppose we have the right triangle ABC

The measure of angle C is 90 degrees

A and B are complementary angles

A+B=90°

therefore

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8 0
4 years ago
Need an answer, please need an answer, please​
dusya [7]

Answer:

Step-by-step explanation:

1) 6  and -5

x₁ + x₂  = 6 +(-5) = 1

x₁* x₂   = 6*(-5) = -30

x² -(x₁ + x₂)x + (x₁* x₂)=0

x² - x  - 30 = 0

2) 4 and 7

x₁ + x₂  =4 + 7 = 11

x₁* x₂   = 4*7 = 28

x² - 11x + 28 = 0

3) 1 and -10

x₁ + x₂  = 1 +(-10) = -9

x₁* x₂   = 1*(-10) = -10

x²  - 9x - 10 = 0

4) -9 and 0

x₁ + x₂  = -9 + 0 = -9

x₁* x₂   = 0

x² - (-9)x  = 0

x² + 9x = 0

5)2 and 6

x₁ + x₂  = 2 + 6 = 8

x₁* x₂   = 2*6 = 12

x² -8x + 12 = 0

8) 2 +√3  and 2 - √3

x₁ + x₂  = 2+ √3 + 2 - √3 = 4

x₁* x₂   = (2 + √3)(2 - √3) = 2² - (√3)² 4 - 3 = 1

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7 0
3 years ago
Find the least common denominator for these two rational expressions. B/b^2 -64 -7b/b^2+7b-8
san4es73 [151]

Answer:

The least common denominator is (b-8)(b+8)(b-1)

Step-by-step explanation:

We are given expression as

\frac{b}{b^2-64}-\frac{7b}{b^2+7b-8}

Firstly, we will factor both denominators

b^2-64=b^2-8^2=(b-8)(b+8)

b^2+7b-8=(b+8)(b-1)

so, we can plug it back

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First term denominator is

(b-8)(b+8)

Second term denominator is

(b+8)(b-1)

So,

Least common denominator will be

(b-8)(b+8)(b-1)

So, we get

LCD=(x-8)(x+8)(x-1)


3 0
3 years ago
The sum of two numbers is 52. The greater number is 4 more than the smaller number. Which equation can be used to solve for the
MA_775_DIABLO [31]

Answer:Let's assume x be the smaller number.

Given that, The greater number is 4 more than the smaller number.

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It's also given that, The sum of two numbers is 52. Which means sum of x and x+4 must be equa to 52. Hence,

x + (x + 4) = 52

Step-by-step explanation:

6 0
2 years ago
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