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OLEGan [10]
3 years ago
5

Jill drives 75 1/3 miles every hour how many miles can Jill Drive in 8 and 3/4 hours

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0
First, multiply 75 by 8 to get 600. 
Then multiply 1/3 by 8 to get 8/3 or 2 2/3. 
Add those together to get 602 2/3. 

Next multiply 1/3 by 3/4 by multiplying the numerator by 3 and the denominator by 4. That is 3/12. Also known as 1/4. 
Multiply 75 by 3/4 by dividing it by 4 then multiplying it by 3. That is 56 1/4. 
Add 56 1/4 and 1/4 together to get 56 1/2. 

Lastly, add together 56 1/2 and 602 2/3.
Convert the fractions to sixths.
56 3/6 + 602 4/6 = 659 1/6 miles
Hope this helps! 
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AleksandrR [38]
N = x/y because  its in the middle
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3 years ago
Find an expression for a cubic function f if f(4) = 96 and f(-4) = f(0) = f(5) = 0. Part 1 of 4 A cubic function generally has t
Bezzdna [24]

Given a polynomial p(x) and a point x_0, we have that

p(x_0) = 0 \iff (x-x_0) \text{\ divides\ } p(x)

We know that our cubic function is zero at -4, 0 and 5, which means that our polynomial is a multiple of

(x+4)(x)(x-5) = x(x+4)(x-5)

Since this is already a cubic polynomial (it's the product of 3 polynomials with degree one), we can only adjust a multiplicative factor: our function must be

f(x) = ax(x+4)(x-5),\quad a \in \mathbb{R}

To fix the correct value for a, we impose f(4)=96:

f(4) = 4a(4+4)(4-5) = -32a = 96

And so we must impose

-32a=96 \iff a = -\dfrac{96}{32} = -3

So, the function we're looking for is

f(x) = -3x(x+4)(x-5)=-3x^3+3x^2+60x

4 0
3 years ago
A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther
mariarad [96]
<h2>Answer:</h2>

<em><u>Recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\

Therefore, on checking, we observe that,

a_{n}=a_{n-1}+(n-1)^{2}

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

<u>At, </u>

<u>n = 1</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0

which is true.

<u>At, </u>

<u>n = 2</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1

Which is also true.

<u>At, </u>

<u>n = 3</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5

Which is true.

<u>At, </u>

<u>n = 4</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14

This is also true at the given value of 'n'.

<em><u>Therefore, the recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

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Answer:

65 miles per day

Give my a brain baby

Step-by-step explanation:

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71. Lesson 3
snow_lady [41]
1. -1
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