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3 years ago

Right 12,430,000 in expanded form

Mathematics

2 answers:

galina1969 [7]3 years ago

8 0

10,000,000+2,000,000+400,000+30,000+0,000+000+00+0 :)

laila [671]3 years ago

6 0

Twelve million, four hundred thirty thousand

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What the next number...2 7 8 3 12 9

ANEK [815]

-(17/30)n^5+(113/12)n^4-(173/3)n^3+ (1915/12) n^2- ( 5813/30)n +85

there fore term number 7 is .... -146/1=-146

5 0

2 years ago

Find inverse of y=1/2x+3

yKpoI14uk [10]

Answer: f⁻¹(x)=2x-6

Step-by-step explanation:

To find the inverse of an equation, you replace y with x and x with y. Then, you solve for y.

y=1/2x+3 [replace y with x and x with y]

x=1/2y+3 [subtract both sides by 3]

x-3=1/2y [multiply both sides by 2]

y=2(x-3) [distribute]

y=2x-6

Now, we know the inverse function is f⁻¹(x)=2x-6.

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2 years ago

What is 2*2 + {[1 x (5 - 2)] x 3}<br><br> * = to the power of<br><br> can anyone please help me?

bearhunter [10]

Answer:

4+{[1x(3)]x3}

4+{[3]x3)

4+9

8 0

2 years ago

A pipe is 10 ft long. It need to be cut into pieces that are each 2/5 feet long. How many pieces can be made from the pipe?

e-lub [12.9K]

The answer is 25. To check 10/.4 is 25 and 0.4 equals to 2/5

3 0

3 years ago

How do you solve an absolute value equation?

Mkey [24]

The distance between two real numbers $x,y$ is the absolute value of their difference, $|x-y|$ . So the statement "all $x$ that are 1/4 away from -6" is captured in the equation

$|x-(-6)|=\dfrac14$

$|x+6|=\dfrac14$

To solve, you can use the definition of absolute value: if $x$ is not negative, then $|x|=x$ ; otherwise, $|x|=-x$ .

So there are two cases to consider:

1. Suppose $x+6\ge0$ . Then $|x+6|=x+6$ , and the equation reduces to

$x+6=\dfrac14\implies x=-\dfrac{23}4$

2. Suppose $x+6$ . Then $|x+6|=-(x+6)=-x-6$ and

$-x-6=\dfrac14\implies x=-\dfrac{25}4$

$-6=-\dfrac{24}4$ , so the two solutions we found are correct because both $-\dfrac{23}4$ and $-\dfrac{25}4$ are indeed 1/4 away from -6.

- - -

For the question regarding inequality, you know that the absolute value must return a non-negative number. In other words, there is no $x$ such that $|x|$ .

6 0

2 years ago