The amount of heat needed to cook the pork roast is 1700 kJ.
The amount of heat absorbed by the roast is 14% of the heat produced = 14% X ?H = 310.38 kJ/mol
One mole of propane burns to produce 3 moles of CO2 and -2217 kJ of heat.
1700kJ/ (14% X ?H) = mol of C3H8 burned
1700kJ / (310.38 kJ/mol) = 5.48 mol C3H8
Since 3 moles of CO2 are produced:
3 X 5.48 mol= 16.43 mols of CO2
convert moles to grams:
16.43 mol CO2 X 44.0g/mol ~ 722.9 g CO2 produced
Simplify:
The equation is already simplified =====> (6x² - x - 1)/(x - 1)
Solve:
Solution (6x² - x - 1)/(x - 1) =======> 6x + 5 + 4/x - 1
Steps:
Apply Long Division on:
(6x² - x - 1)/(x - 1)
Divide:
(6x² - x - 1)/(x - 1):
(6x² - x - 1)/(x - 1) = 6x + 5x - 1/x - 1
= 6x + 5x - 1/x - 1
Divide:
5x - 1/x - 1
5x - 1/x - 1
= 5 + 4/x - 1
Answer ======> 6x + 5 + 4/x - 1
Hope that helps!!!!! : )
Answer:
D
Step-by-step explanation:
3 1/16
Divide 49 by 16 and then multiply the whole number by 16 to find out the 1/16
Answer:
I know what you're asking you are asking to find the least common multiple. However all I can find is the GCF which is 1
Step-by-step explanation:
