Answer:
20m
Step-by-step explanation:
After plotting all the three points, we get the parabolic equation in the form is 2(x - 1)²-34.
<h3>What is parabola?</h3>
Any point on a parabola, which has the shape of a U, is situated at an equal distance from the focus, a fixed point, and the directrix, a fixed line.
General equation of the quadratic equation,
Y = ax² + bx +c
Given points,
(-2, 0),
(-1, -10),
(4, 0).
Putting the points in the general equation,
Putting (-2, 0), we get
0 = 4a - 2b + c
Putting (-1, -10), we get
-10 = a - b +c
Putting (4, 0), we get
0 = 16a + 4b +c
Solving all equations we get,
a = 2 , b = -4 , c = -16
After putting the values,
Y = 2x²- 4x- 16
2(x² - 2x - 8)
2(x²- 2x + 1 - 1 - 16)
=2(x - 1)²-34
Hence we get the required equation in the parabolic form.
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Answer:
The weight of the object is 3 kg.
Step-by-step explanation:
<u>Step 1:
</u>
Let object weight be x kg.
Now, as per the available data,
3/4 kg + 3/4 (x kg) = x kg
<u>Step 2:
</u>
3/4 (1 + x) = x
1 + x = 4x/3
1 = x (4/3 - 1)
x = 1 / (1/3)
x = 3
Weight of Object is 3 kg.
<u>Step 3:
</u>
Let's check if this value satisfies the first equation.
3/4 + 3/4 x 3 = 3/4 + 9/4 = 12/4 = 3
Hence proved.
Tan(58)=10/x
x=10/tan(58)
x= 6.2
Answer:
Step-by-step explanation:
The height of the marshmallow (in feet) is represented by the equation h=−16t2+8t+48,
where t is the time (in seconds) after he throws the marshmallow.
The equation is a quadratic equation. When the marshmallow hits the ground, its height from the ground will be zero. Therefore
−16t^2+8t+48 = 0
- 2t^2 + t + 6 = 0
Multiplying through by the negative sign. It becomes
2t^2 - t - 6 = 0
2t^2 + 3t - 4t - 6 = 0
t(2t + 3) - 2(2t + 3) = 0
(t - 2)(2t + 3) = 0
t - 2 = 0 or 2t + 3 = 0
t = 2 or t = - 3/2
The time cannot be negative
So it will take 2 seconds to hit the ground
