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Whitepunk [10]
3 years ago
14

Amber got a raise, and her hourly wage increased from $8 to $9.50. What is the percent increase?

Mathematics
1 answer:
Papessa [141]3 years ago
5 0

Answer:

18.75%

Step-by-step explanation:

9.50-8/8

=1.5/8

=0.1875

0.1875(100)

=18.75%

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Imagine telling a friend about your favorite coffee and donut shop. Your friend asks how much it charges for a cup of coffee and
Mama L [17]

Answer:

c + 2d = $7.00

2c + 3d = $12.00

Step-by-step explanation:

Hello!

<u>Let:</u>

  • c = # of coffees
  • d = # of donuts

1 coffee and 2 donuts cost $7.00

This can be repesented by 1c + 2d = $7.00, or c + 2d = $7.00

2 coffees and 3 donuts cost $12.00

This can be represented by 2c + 3d = $12.00

<u>So, the system is :</u>

c + 2d = $7.00

2c + 3d = $12.00

8 0
3 years ago
Mr. Carlevato and Mr. Burrows get into a debate about two different expressions. · Mr. Carlevato says "2(2x + 3) is equal to 4x
ruslelena [56]

Answer:

Yes, the same answer is obtained.

Step-by-step explanation:

According to Mr. Carlevato, 2(2x+3) is equal to 4x+6. However, 2(2x+3) is not equal to 4x+6 according to Mr. Burrows.

Put x=5 in 2(2x+3)

2[2(5)+3]=2(10+3)=2(13)=26

Put x=5 in 4x+6

4x+6=4(5)+6=20+6=26

Therefore,

2(2x+3)=4x+6

Yes, the same answer is obtained.

3 0
3 years ago
The equation y = 6.3x + 67.4 is the equation of a linear model in a scatter plot comparing the ages of boys between 2 and 10 yea
mihalych1998 [28]
Y = 6.3x + 67.4
The average height of a 5 year old boy is
 6.3(5) + 67.4 = 31.5 + 67.4 = 98.9 cm
7 0
3 years ago
Read 2 more answers
Evaluate (x^3-x^2-3x+8)+(2x^3+3x^2+x-7)
dolphi86 [110]

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: 3x^3+2x^2-2x+1

Explanation:

x^3 + 2x^3 - x^2 + 3x^2 -3x + x + 8 - 7 = 3x^3+2x^2-2x+1

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

4 0
3 years ago
Can someone just tell me if these answers are right?
7nadin3 [17]
Ok I will tell you if they are right


8 0
4 years ago
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