11+3(9-6)-4= Please do it step by step.

2 answers:

6 0

11+3(9-6)-4 11+3(3)-4 note always do what's in parenthesis first 11+3(3)-4 11+9-4 note work from the left to the right when doing addition and subtraction 11+9-4 20-4 16 16 is your under

tester [92]2 years ago

3 0

11+3=14*(9-6=3)-4=38

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A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

2 years ago

If the Revenue for the week is $2000, and labor cost consists of two workers earning $8 per hour who work 40 hours each, what is

Hatshy [7]

2 workers, each 8 per hour, for 40hrs a week, so one earns 8 * 40, or 320 bucks, is two workers, so 320 + 320 or 640 bucks

if 2000 is the 100%, how much is 640 in percentage off of it?

well $\bf \begin{array}{ccllll}
amount&\%\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
2000&100\\ 640&x
\end{array}\implies \cfrac{2000}{640}=\cfrac{100}{x}$

solve for "x"

7 0

2 years ago

Read 2 more answers

-0.4a+3=7<br><img src="https://tex.z-dn.net/?f=%20-%200.4a%20%2B%203%20%3D%207" id="TexFormula1" title=" - 0.4a + 3 = 7" alt=" -

natali 33 [55]

Sorry if I'm wrong
a = 10
this what I did
7 - 3 = 4 ÷ 0.4 = 10

5 0

3 years ago

If A and B are independent events PA equals .25 and B equals .3 what is P a/b

jeka57 [31]

The a is idshdvsvehdhdbdhdhggansnsbfsbshd

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