5,082 balls golf balls would fit in a 55 gallon drum.
<u>Solution:</u>
Given,
Radius of a golf ball = 0.840 inches
[Pi = 3.14]




Answer:
hello
Step-by-step explanation:
Answer: 49/60
Step-by-step explanation:
(1/3+2/5)-1/4-(5/6-7/6)
Primero (5/6-7/6)
5/6-7/6=-2/6
1/3+2/5-1/4-(-2/6)
1/3+2/5-1/4+2/6
2/6=1/3
1/3+2/5-1/4+1/3
2/3+2/5-1/4
2/3=10/15
2/5=6/15
10/15+6/15-1/4
16/15-1/4
16/15=64/60
1/4=15/60
64/60-15/60=49/60
<h3>
The dimensions of the given rectangular box are:</h3><h3>
L = 15.874 cm , B = 15.874 cm , H = 7.8937 cm</h3>
Step-by-step explanation:
Let us assume that the dimension of the square base = S x S
Let us assume the height of the rectangular base = H
So, the total area of the open rectangular box
= Area of the base + 4 x ( Area of the adjacent faces)
= S x S + 4 ( S x H) = S² + 4 SH ..... (1)
Also, Area of the box = S x S x H = S²H
⇒ S²H = 2000

Substituting the value of H in (1), we get:

Now, to minimize the area put :

Putting the value of S = 15.874 cm in the value of H , we get:

Hence, the dimensions of the given rectangular box are:
L = 15.874 cm
B = 15.874 cm
H = 7.8937 cm