Your answer is C.
Hope this helped.
Answer:
The solution of the system is the ordered pair (-13,-4)
Step-by-step explanation:
we have
-----> equation A
----> equation B
Solve the system by elimination
Multiply by 2 both sides equation B
----> equation C
Adds equation A and equation C
![-2a+3b=14\\2a-8b=6\\-------\\3b-8b=14+6\\-5b=20\\b=-4](https://tex.z-dn.net/?f=-2a%2B3b%3D14%5C%5C2a-8b%3D6%5C%5C-------%5C%5C3b-8b%3D14%2B6%5C%5C-5b%3D20%5C%5Cb%3D-4)
<em>Find the value of a</em>
substitute the value of b in any equation (i take equation B)
![a-4(-4)=3](https://tex.z-dn.net/?f=a-4%28-4%29%3D3)
![a+16=3](https://tex.z-dn.net/?f=a%2B16%3D3)
![a=-13](https://tex.z-dn.net/?f=a%3D-13)
therefore
The solution of the system is the ordered pair (-13,-4)
We must take into account the following change of units:
![1kw = 1000w 1 year = 365 days 1 day = 24 hours](https://tex.z-dn.net/?f=1kw%20%3D%201000w%0A%0A1%20year%20%3D%20365%20days%0A%0A1%20day%20%3D%2024%20hours)
Applying the change of units we have that the electric consumption for 1 year is given by:
![(3) * (1/1000) * (365) * (24) = 26.28 kw * h ](https://tex.z-dn.net/?f=%283%29%20%2A%20%281%2F1000%29%20%2A%20%28365%29%20%2A%20%2824%29%20%3D%2026.28%20kw%20%2A%20h%0A)
Then, the total cost is given by:
Answer:
the cost of operating a 3.00-w electric clock for a year is:
$ 2.3652
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Price of home = $220,000
Down payment = 20%
3 points at closing
30 years fixed rate mortgage at 7%
A.)The down payment :
20% of price
0.2 × $220,000 = $44,000
B.) Amount of the Mortgage :
Price - down payment
$220,000 - $44,000 = $176,000
C.) Amount to be paid for the 3 point of closing :
3% of mortgage amount
0.03 * $176,000 = $5,280
D.) monthly payment :
(mortgage amount(1 + rate)) / 30* 12
176000(1 + 0.07)
($176,000 + $12320) / 360
$523
E.) Total cost of interest :
0.07 * 176000 = $12,320