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aleksandrvk [35]
3 years ago
14

Show work for this fraction 1 2/3-3/4

Mathematics
1 answer:
statuscvo [17]3 years ago
4 0
1\frac23-\frac34

Write 1 2/3 as an improper fraction...
1 = 3/3. Plus the 2/3 makes 5/3.

\frac53-\frac34

To add/subtract fractions, they need the same denominator. (bottom number)

We can change the denominator by multiplying the top and bottom of a fraction by the same number. (it will stay equal, like 1/2 and 2/4)

Let's change 5/3 and 3/4 to a denominator of 12.

5/3 = 20/12 (bottom multiplies by 4, so does the top)
3/4 = 9/12 (bottom multiplies by 3, so does the top)

\frac{20}{12}-\frac9{12}

Now we just subtract the 20 minus 9 twelfths. (the twelfths act as a sort of unit)

\boxed{\frac{11}{12}}
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Find Each Difference 125 - ( -114 )​
joja [24]

Answer:

125-(-114)=239

Step-by-step explanation:

Change the subtraction to addition and change the negative in the second number to a positive (it's the opposite). Then add them. 125+114=239

CAN EXPLAIN FURTHER

6 0
3 years ago
Ava is going to the county fair. The cost of admission is $5.50 and it is $1.50 for each ride. If Ava has $19.00, Write and solv
snow_tiger [21]

Answer:

5.50 + 1.50x = 19

x = 9

Ava can ride <u>9</u> rides.

Step-by-step explanation:

5.50 + 1.50x = 19

-5.50                -5.50

1.50x = 13.50   (divide both sides by 1.50)

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8 0
3 years ago
Identify the number and type of solutions for the equation 3x2 + 2x + 9 = 0.
Marizza181 [45]

Step-by-step explanation:

3×2+2x+9=0

6+2x=0-9=-9

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×=-7.5

5 0
3 years ago
Read 2 more answers
Determine if the following lines are parallel, perpendicular, or neither
Nookie1986 [14]
Parallel
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4 0
3 years ago
Find the sum of the three smallest positive values of θ such that <img src="https://tex.z-dn.net/?f=4%5Ccos%5E2%282%5Ctheta-%5Cp
Harlamova29_29 [7]

Answer:

∅= 13π/12

Step-by-step explanation:

Solve until you get cos(___) on one side and a value on the other side.

I got cos(2∅-π) = ±√(3)/2

I know that the only cos() value that gives me  ±√(3)/2 are -5π/6, -π/6, and π/6 from looking at the unit circle; those 3 are the smallest value that would give me  ±√(3)/2.

So i solve for what value of 2∅-π would give me -5π/6, -π/6, and π/6

by solving for

2∅₁-π = -5π/6,   2∅₂-π = -π/6,   and 2∅₃-π = π/6

I got ∅₁=π/12, ∅₂=5π/12, ∅₃=7π/12.

The question wanted the sum of the three smallest value so i added it up and got 13π/12.

And thanks for peer review. Good catch on my mistakes.

3 0
4 years ago
Read 2 more answers
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