All categories

3 years ago

What is the probability that Omar will get to drive the car after the first roll?

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

7 0

Answer:

1/6

Step-by-step explanation:

For Omar to drive, he has to get a six when a die is rolled ;

The probability that Omar will get to drive his car is :

Required outcome = (6) = 1

Total possible outcomes = (1,2,3,4,5,6)

P(rolling a 6) = required outcome / Total possible outcomes

P(rolling a 6) = 1/6

Probability of Omar driving his car is 1/6

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1. Two object accumulated a charge of

In-s [12.5K]

Answer:

The magnitude of the electric force between these two objects

will be: 181.274 N.

i.e. F $=181.274$ N

Step-by-step explanation:

Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8 μC = 2.8 × 10⁻⁶ C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

$F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}$

$=\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $\mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4$

$\mathrm{Cancel\:the\:common\:factor:}\:10^{-12}$

$=\frac{12.6}{35.4\pi \left(10^{-2}\times \:2.5\right)^2}$

$=\frac{12.6}{0.025^2\times \:35.4\pi }$ ∵ $\left(10^{-2}\times \:2.5\right)^2=0.025^2$

$=\frac{12.6}{0.022125\pi }$ ∵ $35.4\pi\times 0.025^2=0.022125\pi$

$=\frac{12.6}{0.06950 }$

F $=181.274$ N

Therefore, the magnitude of the electric force between these two objects will be: 181.274 N.

i.e. F $=181.274$ N

7 0

3 years ago

I need help ☹️☹️☹️ please!!!!!!!!!!

aliina [53]

Answer: 1st one

Step-by-step explanation:

4 0

3 years ago

The quotient of m and 11 minus 3 as a algebraic expression

PilotLPTM [1.2K]

(m/11) - 3
Doing the quotient first so I put it in parenthesis, then subtract 3

3 0

3 years ago

One group (A) contains 390 people. Three-fifths of the people in group A will be selected to win $100 fuel cards. There is anoth

svetoff [14.1K]

The ratio of nonwinners in group A to nonwinners in group B after the selections are made is 156 : 319.

<h3>What is the ratio?</h3>

Ratio expresses the relationship between two or more numbers. It shows the frequency of the number of times that one value is contained within other value(s).

Nonwinners in group A = (1 - 3/5) x 390 = 156

Winners in group B = (390 - 156) = 234

nonwinners in group B = 553 - 234 = 319

The ratio = 156 : 319

To learn more about ratios, please check: brainly.com/question/25927869

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5 0

3 years ago

1. What is the solution of n² – 49 = 0? (1 point)

maks197457 [2]

Answer:

1. $n=\pm7$