The probability that the train will be there when Alex arrives is 5/18
If Alex arrives at any time after 1.20pm the chances that train will be there is 1/3.
However if alex arrives at 1.00pm exactly there is no chance the train will be arrive there.
The probability that the train will be there increase linearly to 1/3 as alex's arrival time moves from 1.00pm to 1.20pm.
By arranging the probabilities over the first 20 minutes to get a 1/6 chance the train will be there if alex arrives between 1.00pm to 1.20pm
we get the final answer by
=1/3( 1/6 + 1/3 + 1/3)
=5/18
So, the probability that the train will be there when Alex arrives is 5/18
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First isolate x by multiplying by x on both sides. It will look like this:
(2/3)x=1.2
Then devise by (2/3) on both sides to get:
x= 1.2/(2/3)
The easiest way to get this is plug that into a calculator and get the answer:
x=1.8
T -1,-1 ect ect hope helps
Slope = 2/3 (positive 2/3)
You use the formula Y2-Y1/X2-X1 in order to get the slope
Answer:
So the time is 5:17 a.m.
Explanation:
Note that:
11:32 pm is 28 minutes before midnight.
Adding the 534 hours will take the time into early morning.
So all we need to do to find the new time (am) is to subtract 28 minutes from 534 hours.
534→5 hours and 45 minutes
Subtracting the minutes:
45
28−− ← Subtract
17
So the time is 5:17 a.m.
