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IgorC [24]
3 years ago
5

Determine if the following lines are parallel, perpendicular, or neither

Mathematics
1 answer:
Nookie1986 [14]3 years ago
4 0
Parallel
perpendicular
parallel
neither
perpendicular
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Find an equation of the line that satisfies the given conditions. through (−5, −7); perpendicular to the line passing through (−
murzikaleks [220]

Answer:

The equation would be y = 2x + 3

Step-by-step explanation:

In order to solve this, we first need to find the slope of the line between (-2, 5) and (2, 3). In order to do this, we use the slope formula.

m(slope) = (y2 - y1)/(x2 - x1)

m = (3 - 5)/(2 - -2)

m = -2/4

m = -1/2

Now that we have the original line with a slope of -1/2, we can tell a perpendicular line would have a slope of 2. This is because perpendicular lines have opposite and reciprocal slopes. Now we can use that slope and the given point in point-slope form to get the answer. Be sure to solve for y.

y - y1 = m(x - x1)

y + 7 = 2(x + 5)

y + 7 = 2x + 10

y = 2x + 3

7 0
3 years ago
A generator can run for 11 hours on 3 gallons of gasoline. How many hours can the generator run on 9 gallons of gasoline?
Margarita [4]

Answer:

11 / 3 hours

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
-3(-6u+6)-3u=5(u-2)-3
riadik2000 [5.3K]

Answer:

u=1/2

Step-by-step explanation:

-3(-6u+6)-3u=5(u-2)-3

18u-18-3u=5u-10-3

15u-18=5u-13

15u-5u-18=-13

10u-18=-13

10u=-13+18

10u=5

u=5/10

simplify

u=1/2

5 0
3 years ago
Determine the intercepts of the line.
Charra [1.4K]

Answer:

x-intercept: None

y-intercept: (0,-18)

5 0
3 years ago
Point M is the midpoint of AB. If the coordinates of M are (2,8) and the coordinates of A are (10,12),what are the coordinates o
ElenaW [278]

~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{10}~,~\stackrel{y_1}{12})\qquad B(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ x + 10}{2}~~~ ,~~~ \cfrac{ y + 12}{2} \right)~~=~~\stackrel{M}{(2,8)}\implies \begin{cases} \cfrac{x+10}{2}=2\\[1em] x+10=4\\ \boxed{x=-6}\\[-0.5em] \hrulefill\\ \cfrac{y+12}{2}=8\\[1em] y+12=16\\ \boxed{y=4} \end{cases}

4 0
2 years ago
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