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Mandarinka [93]
3 years ago
12

Find

latex-formula"> for the function f(x)= \sqrt[3]{x-2}+8.
A. f^{-1}(x)=(x-8)^3+2
B. f^{-1}(x)=(x+8)^3+2
C. f^{-1}(x)= \sqrt[3]{x-8} +2
D. f^{-1}(x)=(x-8)^3-2
Mathematics
1 answer:
Katen [24]3 years ago
5 0
The f⁻¹ means that you have to find the inverse of the given original function. The solution is shown below. First, interchange the x and y variables, then solve for y. 

f(x) = ∛(x - 2) + 8
y = ∛(x - 2) + 8
x = ∛(y - 2) + 8
x - 8 = ∛(y - 2)
[x - 8 = ∛(y - 2)]³
(x - 8)³ = y - 2
y = (x - 8)³ + 2
f⁻¹(x) = (x - 8)³ + 2

The answer is A.
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Solve the system using the elimination method.
spayn [35]

Answer:

  (x, y, z) = (-22/13, 29/13, 6/13)

Step-by-step explanation:

Adding the first and second equations, we get ...

  (3x +2y -3z) +(7x -2y +5z) = (-2) +(-14)

  10x +2z = -16 . . . . collect terms

  5x + z = -8 . . . . . . divide by 2 . . . [eq4]

Adding twice the second equation to the third, we get ...

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  16x +11z = -22 . . . . . . [eq5]

Now, we have two equations with the variable y eliminated. We can subtract [eq5] from 11 times [eq4] to eliminate z:

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  x = -66/39 = -22/13

From [eq4], we can find z as ...

  z = -8 -5x = -8 -5(-22/13) = 6/13

And from the second equation, we get ...

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The solution is (x, y, z) = (-22/13, 29/13, 6/13).

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3 years ago
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