Given:
- Bought n items of product A at 1/5 rs each
- bought n items of product B at 1/4 rs each
He mixed the two items and sold each at 2/9 rs each.
He lost 3 rs in the above batch of articles.
Solution:
revenue = 2n* (2/9) rs = 4n/9 rs
cost = n/5+n/4 rs = n(1/5+1/4)
Profit = revenue-cost = 4n/9-n(1/5+1/4) = -3 rs
Solve for n
4n/9-n(1/5+1/4) = -3
factor out n
n(4/9-1/5-1/4)=-3
n(80-36-45)/180=-3
-n/180=-3
n=3*180=540
Total number of products bought
= n+n = 540+540 = 1080
Answer:
see explanation
Step-by-step explanation:
y(x + 1) = 51 ← substitute y = 3 into the equation
3(x + 1) = 51 ( divide both sides by 3 )
x + 1 = 17 ( subtract 1 from both sides )
x = 16
Answer:
A True
Step-by-step explanation:
tell me if I'm worng
Answer:
No Solutions
Step-by-step explanation:
Step 1:
5x + 9 = 2x + 7 + 3x - 15 Equation
Step 2:
5x + 9 = 5x - 8 Add and Subtract
Step 3:
9 = - 8 Subtract 5x on both sides
Answer:
9 ≠ - 8 9 cannot equal - 8
Hope This Helps :)
is this a school qustion? if not
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