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marissa [1.9K]
3 years ago
7

Marissa and haylie met for dinner in downtown Savannah. Marissa did flat-rate valet parking for $20. Haylie went to another vale

t and paid $5 up front and $2.50 for every hour, including the first hour. Ultimately the friends end up paying the same amount. How long did they stay? How much did each one pay?
Mathematics
1 answer:
shtirl [24]3 years ago
4 0

Answer:

6 hours; each paying $20

Step-by-step explanation:

To start off, we know that Marissa paid exactly $20 for parking. Since we know that Marissa and Haylie paid the same amount, we must now move on to Haylie.

Haylie paid $5 upfront. Now we must figure out how many hours Haylie must have stayed if each hour costed $2.50. We can figure this out by dividing $15 by $2.50 since Haylie already paid $5 upfront.

$15 / $2.50 = 6

This means that Haylie and Marissa stayed for 6 hours and paid exactly $20 dollars each.

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Step-by-step explanation:

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3 years ago
What is the value of the x variable in the solution to the following system of equations?
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-2 (x-2y=-5)

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6 0
3 years ago
The current population of a town is 10,000 and its growth in years can be represented by P(t) = 10,000(0.2)^t, where t is the ti
DiKsa [7]

Answer:

1) 20%

2) Choice a.

Step-by-step explanation:

P(t)=10000(0.2)^t

1) P(0) is the population initially.

P(1) is the population after a year.

\frac{P(1)}{P(0)} represents the population increase factor.

So let's evaluate that fraction:

\frac{P(1)}{P(0)}

\frac{10000(0.2)^1}{10000(0.2)^0}

\frac{0.2^1}{0.2^0}=\frac{0.2}{1}=0.2

0.2=20%

2) Let's figure out the population growth in terms of months instead of years.

P(t)=10000(0.2)^{t}

We want t to represent months.

A full year is 12 months, in a full year we have that P(1)=10000(0.2)^1=10000(0.2)=2000

So we want a new P such that P(12)=2000 since 12 months equals a year.

Let's look at the functions given to see which gives us this:

a) P(12)=10000(0.87449)^{12}=2000 \text{approximately}

b) P(12)=10000(0.87449)^{12(12)}=0 \text{ approximately}

c) P(12)=10000(0.87449)^{\frac{1}{12}}=9889 \text{approximately}

d) P(12)=10000(0.87449)^{12+12}=400 \text{approximately}

So a is the function we want.

Also another way to look at this:

P(t)=10000(.2)^t where t is in years.

P(t)=10000(.2^\frac{1}{12})^t where t is in months.

And .2^\frac{1}{12}=0.874485 \text{approximately}

8 0
4 years ago
Is the following a function?
saw5 [17]

Answer:

yes

Step-by-step explanation:

For the relation to be a function, there must only be one corresponding value of y (range) for any value of x in the domain, that is a one-to- one relationship

This graph displays this feature and is a function.


5 0
3 years ago
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Here's the link to the answer.. 69.08
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