Answer:
- Initial amount of the material is 67 kg
- Hal-life is 83 hours
<u>The required equation is:</u>
- m(x) = 67 *
, where m- remaining amount of the radioactive material, x - number of hours
<u>After 5 hours the material remains:</u>
- m(5) = 67 *
= 64.260 (rounded)
Answer:(-5,-6)
Step-by-step explanation:
Solve for one variable then solve for the other. Don’t worry you will get a big fraction before you get to the whole number.
Answer:
The answer would be 5/6.
Step-by-step explanation:
So if we want to know the least amount, we first want to assume the other two games both had a score of 52, so we can say the last one had the least possible.
So if both got 52, the total points would be 104, for two games of 52 points. Since we want 141 points, we therefore want 37 more points to reach 141.
So the least amount of points a player could've scored in one of the games was 37.
Part 1:
You have the correct answer. You multiply the probability of getting red (6/15) by the probailitiy of getting red (6/15) to get 36/225 which reduces to 4/25
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Part 2:
This is also correct. Nice work. You multiply the probability of getting black (9/15) with the probability of getting red (6/15) to get 54/225 = 6/25
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Part 3:
The probability of picking a black checker is 9/15. If a replacement is made, then the probability of picking another black checker is also 9/15. So,
(9/15)*(9/15) = 81/225 = 9/25
Answer: 9/25
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Part 4:
The probability of rolling a 6 is 1/6. The probability of rolling a 3 is 1/6 as well. This is because there is only one side with this label out of 6 total. Multiply the probabilities
(1/6)*(1/6) = 1/36
Answer: 1/36
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Part 5:
It is impossible to roll a 7 on the six sided cube because the highest number is 6. Therefore the overall probability is 0
Answer: 0
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Part 6:
There are 3 outcomes we want (rolling a 1,2, or 3) out of 6 total. So the probability of rolling a 1,2 or 3 is 3/6 = 1/2. Similarly, the probability of rolling a 4, 5 or 6 is 3/6 = 1/2 as well.
Multiplying the probabilities gives
(1/2)*(1/2) = 1/4
Answer: 1/4
