Answer:
Option (3)
Step-by-step explanation:
Joe has a ruler which has markings for each millimeter, so the least measurement which Joe can do is in millimeter.
Since, 10 mm = 1 cm
Therefore, 1 mm = 0.1 cm
This rule states that Joe can measure a length or distance in nearest tenth of a cm only.
If length of a box = 13.67 cm,
So Joe can measure it as 13.7 cm approximately.
Therefore, Option (3) will be the answer.
The answer to A. is 108cm or 1.08m
First convert 2m to cm:
2m x 100 = 200 cm
Next convert 6m to cm:
6m x 100 = 600 cm
Divide the height of the person by his/her shadow:
200cm ÷ 600cm = <span>0.33333333333 = .3</span>
Multiply 360cm by .3:
360cm x .3 = 108cm
108cm ÷ 100 = 1.08m
The answer to B. is 6.8 cm.
The scale seems a bit small... are you sure you don't mean 0.8 m?
a = length of actual car.
8.5 x 0.8 = 1 x a
6.8 = 1 x a
6.8 ÷ 1 = a
6.8 = a
If you did mean 0.8 m... the answer is 680 cm or 6.8 m.
a = length of actual car.
0.8m x 100 = 80cm
8.5 x 80 = 1 x a
680 = 1 x a
680 ÷ 1 = a
680 = a
680 ÷ 100 = 6.8
There are different kinds of math problem. There will be 11 rats in sewer #1.
<h3>What are word problem?</h3>
The term word problems is known to be problems that are associated with a story, math, etc. They are known to often vary in terms of technicality.
Lets take
sewer #1 = a
sewer #2 = b
sewer #3 = c
Note that A=B-9
So then you would have:
A=B-9
B=C- 5
A+B+C=56
Then you have to do a substitution so as to find C:
(B- 9) + (C-5) + C = 56
{ (C- 5)-9} + (C-5) + C = 56
3C - 19 = 56
3C = 75
B = C- 5
B = 25 - 5
Therefore, B = 20
A = B - 9
= 25 - 9
=11
Therefore, there are are 11 rats in sewer #1
Learn more about Word Problems from
brainly.com/question/21405634
The red arrows mean the lines are parallel. Since all angles are equal, the larger triangle is similar to the smaller one. Then corresponding sides have the same ratio
(4x -2)/9 = (3x+2)/12
x(4/9 -3/12) = (2/12) +(2/9)
x = (7/18)/(7/36) = 2 . . . . . . . . . corresponding to the 3rd selection
Answer:
B. 32%
Step-by-step explanation:
16/50 = 32% lol
goodluck!
