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2 years ago

Help me with thisss simplify : 6³/6⁶

1 answer:

7 0

<h2> $= \frac{ {6}^{3} }{ {6}^{6} }$ </h2><h2> $= {6}^{(3 - 6)}$ </h2><h2> $= {6}^{ - 3}$ </h2><h2> $= \frac{1}{ {6}^{3} }$ </h2><h2> $= \frac{1}{6 \times 6 \times 6}$ </h2><h2> $= \frac{1}{216}$ </h2>

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I need help proving this ASAP

Ket [755]

Answer:

See explanation

Step-by-step explanation:

We want to show that:

$\tan(x + \frac{3\pi}{2} ) = - \cot \: x$

One way is to use the basic double angle formula:

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{ \sin(x) \cos( \frac{3\pi}{2} ) + \cos(x) \sin( \frac{3\pi}{2}) }{\cos(x) \cos( \frac{3\pi}{2} ) - \sin(x) \sin( \frac{3\pi}{2}) }$

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{ \sin(x) ( 0) + \cos(x) ( - 1) }{\cos(x) (0) - \sin(x) ( - 1) }$

We simplify further to get:

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{ 0 - \cos(x) }{0 + \sin(x) }$

We simplify again to get;

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = \frac{- \cos(x) }{ \sin(x) }$

This finally gives:

$\frac{ \sin(x + \frac{3\pi}{2} ) }{\cos(x + \frac{3\pi}{2} )} = - \cot(x)$

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3 years ago

Write an equation for the sum of x and 3 minus 2 is 12

Temka [501]

Answer:

x + (3-2) = 12

Step-by-step explanation:

x + (3-2) = 12

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2 years ago

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3 years ago

Question 1<br> 2 (4x - 1) + 6<br> Equivalent to what

WARRIOR [948]

Answer:

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Step-by-step explanation:

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8 0

2 years ago

Read 2 more answers