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Marrrta [24]
3 years ago
12

Help me with thisss simplify : 6³/6⁶

Mathematics
1 answer:
Scrat [10]3 years ago
7 0

<h2>=  \frac{ {6}^{3} }{  {6}^{6} }</h2><h2>=  {6}^{(3 - 6)}</h2><h2>=  {6}^{ - 3}</h2><h2>=  \frac{1}{ {6}^{3} }</h2><h2>=  \frac{1}{6 \times 6 \times 6}</h2><h2>=   \frac{1}{216}</h2>

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5. The amount of time, t, to finish a race and<br> the number of laps, I, around a track
lana [24]

Answer:

T= I x 60 to get minutes(convert to hours if needed)

Step-by-step explanation:

This will get you the amount of time it takes depending on the tracks

7 0
3 years ago
What is (9+8)/(88+77)
barxatty [35]

Answer:

Exact form: 17/165

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Step-by-step explanation:

hope this helps :)

3 0
3 years ago
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Step-by-step explanation:

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7 0
3 years ago
Suppose that 16 inches of wire costs 48 cents. At the same rate, how many inches of wire can be bought for 33 cents?
LenaWriter [7]
11

16/48=0.33333333333
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3 0
3 years ago
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A body was found at 10 a.m. in a warehouse where the temperature was 40F. The medical examiner found the temperature of the body
lawyer [7]
Newton's law of cooling states that under forced convection (which is assumed to be true), then
dT(t)/dt = -k(T(t)-Ta)..............(1)
T(t)=temperature
Ta=ambient temperature=40F
k=cooling constant = 0.1947
T(0)=98.6F (assuming victim did not have fever)
Integrate (1)
T(t)-Ta=(T(t)-T(0))e^(-kt)
Solve for t
(T(t)-Ta)/(T(t)-T(0)) = e^(-kt)
take log:
-kt=log_e((T(t)-Ta)/(T(t)-T(0)))
substitute T(t)=80F, Ta=40F,T(0)=98.6F
-kt=log_e((80-40)/(98.6-40))=-0.38186
t=0.38186/0.1947
=1.96, or almost 2 hours   (assuming k=0.1947 is in hours)
7 0
3 years ago
Read 2 more answers
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