Answer:
π/36 sec-1
Step-by-step explanation:
From the question we are given the formula below
s = rwt ..........eqn(1)
Where s= π/3m, r=3 m, t= 4 sec
We were not given value of " w" which implies we are required to find out values of" w"
We can make " w " the subject of the formula from eqn(1)
s = rwt
w= s/(rt)........eqn(2)
Then substitute for the values in eqn(2)
w= (π/3m ) / ( 3m × 4 sec)
= π/36 sec-1
Hence, the value of the
missing variable is π/36 sec-1
your answer should be 58 correct me if I'm wrong.
Yes you have the right idea. You find the derivative to get the velocity function and then determine when the velocity is zero. That turns out to be at t = 2 and t = 6. Both are correct. The final answer is correct.
The only flaw I see is that you wrote
x'(t) = 3y^3 - 24t + 36
on line 2 when it should be
x'(t) = 3t^2 - 24t + 36
Other than that it looks perfect.
Answer:
y"(2, 1) = -5
Step-by-step explanation:
Step 1: Define implicit differentiation
5 - y² = x²
Step 2: Find dy/dx
- Take implicit differentiation: -2yy' = 2x
- Isolate y': y' = 2x/-2y
- Isolate y': y' = -x/y
Step 3: Find d²y/dx²
- Quotient Rule: y'' = [y(-1) - y'(-x)] / y²
- Substitute y': y" = [-y - (-x/y)(-x)] / y²
- Simplify: y" = [-y - x²/y] / y²
- Multiply top/bottom by y: y" = (-y² - x²) / y³
- Factor negative: y" = -(y² + x²) / y³
Step 4: Substitute and Evaluate
y"(2, 1) = -(1² + 2²) / 1³
y"(2, 1) = -(1 + 4) / 1
y"(2, 1) = -5/1
y"(2, 1) = -5
It should be 5√3
Because 25 x 3 = 75
√25=5 so u bring that out and keep the 3 in because it’s a prime number
