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3 years ago

I NEED HELP WITH THIS. PLEASE HELP. I'M GETTING GRADED ON IT TODAY.

Mathematics

2 answers:

Softa [21]3 years ago

7 0

Answer:

OSCARYNNNNNNNNNNNNNNNN

Step-by-step explanation:

choli [55]3 years ago

3 0

Answer:

Point P = (-9,11)

Step-by-step explanation:

Point M: (1,3) X and Y have the 2 on the bottom right of them

Midpoint N: (-5,7)

Point P: (X*2, Y*2)

( 1 + X*2 3 + Y*2 )

( _______ ________ ) = (-5 , 7)

( 2 , 2 )

( 1 + X*2 )

( _____ ) = -5

( 2 )

Then multiply the left equation above by 2, and that cancels out the 2 being

divided on the bottom. Also, multiply the -5 by 2 and you get -10

1 + X*2 = -10

+1 +1

__________

X*2 = -9

X = -9

( 3 + Y*2 )

( ______ ) = 7

( 2 )

Then multiply the left equation above by 2, and that cancels out the 2 being divided on the bottom. Also, multiply the 7 by 2 and you get 14

3 + Y*2 = 14

-3 -3

_________

Y*2 = 11

Y = 11

Hope this helps, good luck! :)

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F(x) = 3x + 8; g(x) = 5x - 9 (a) Find (f + g)(x).

AysviL [449]

Answer: f(x) = 8x -1

Step-by-step explanation:

( f + g )x = 3x + 5x + 8 - 9

( f + g)x = 8x - 1

8 0

3 years ago

Willow Brook National Bank operates a drive-up teller window that allows customers to complete bank transactions without getting

slega [8]

Answer:

(a) λ = 2.

(b) P (X = 0) = 0.1353; P (X = 1) = 0.2706;

P (X = 2) = 0.2706; P (X = 3) = 0.1804

Step-by-step explanation:

Let X = number of arrivals at the drive-up teller window.

The average number of arrivals at the drive-up teller window per minute is,

p = 0.4 customers/ minute.

(1)

Compute the expected number of customers at the drive-up teller window in n = 5 minutes as follows:

$E(X)=\lambda\\=np\\=5\times 0.4\\=2$

Thus, the mean number of customers that will arrive in a five-minute period is λ = 2.

(2)

The random variable X follows a Poisson distribution with parameter λ = 2.

The probability mass function of X is:

$P(X=x)=\frac{e^{-2}2^{x}}{x!};\ x=0,1,2,3...$

Compute the probability of exactly 0 arrivals in 5 minutes as follows:

$P(X=0)=\frac{e^{-2}2^{0}}{0!}=\frac{0.1353\times 1}{1}=0.1353$

Compute the probability of exactly 1 arrivals in 5 minutes as follows:

$P(X=1)=\frac{e^{-2}2^{1}}{1!}=\frac{0.1353\times 2}{1}=0.2706$

Compute the probability of exactly 2 arrivals in 5 minutes as follows:

$P(X=2)=\frac{e^{-2}2^{2}}{2!}=\frac{0.1353\times 4}{2}=0.2706$

Compute the probability of exactly 3 arrivals in 5 minutes as follows:

$P(X=3)=\frac{e^{-2}2^{3}}{3!}=\frac{0.1353\times 8}{6}=0.1804$

Thus, the values are:

P (X = 0) = 0.1353

P (X = 1) = 0.2706

P (X = 2) = 0.2706

P (X = 3) = 0.1804

(3)

Delays occur in the service time if there are more than three customers arrive during any five-minute period.

Compute the probability that there are more than 3 customers as follows:

P (X > 3) = 1 - P (X ≤ 3)

$=1-\sum\limits^{3}_{x=0}{\frac{e^{-2}2^{x}}{x!}}\\=1-(0.1353+0.2706+0.2706+0.1804)\\=1-0.8569\\=0.1431$

Thus, the probability that delays will occur is 0.1431.

3 0

4 years ago

HelpppppPpapPPapPapp

Dmitriy789 [7]

Step-by-step explanation:

we have two lines you have to draw.

one is all in the bottom left quadrant (for x<=0) and one in the upper right quadrant (for x>5).

the easiest is for x>5. the line function is only

f(x) = y = 3

so, this is a horizontal line on the grid line for y = 3. it starts above x=5 and then goes all the way to the right ("to infinity and beyond !"). just, if possible, mark the starting point at x=5 as a little empty "circle" instead of a full dot, as x=5 is explicitly excluded (due to x>5).

and for x<=0 the line

f(x) = y = 4x - 3

goes sharp down but goes a little bit to the left the further down it goes. it starts with x=0, which gives y=-3 per the function.

so, the starting point (with a full dot, as x=0 is included) is (0,-3).

from there it goes sharp down and a little bit to the left.

for example the next point is for x=-1, which gives y=-7, so it is the point (-1,-7). x=-2 gives y=-11 and the point (-2,-11).

the line has to go through so these points and further down (again, "to infinity and beyond !"), as to move further left on the negative x-axis.

3 0

3 years ago

If (x2 – 4) = (x + 2) = x -2, which polynomial should fill in the blank below?

nalin [4]

Step-by-step explanation:

use the identity a²-b²=(a-b)(a+b)

x²-4=(x-2)(x+2)

so the answer is x-2

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4 years ago

A class consists of 1/2 freshmen, 1/8 sophomores, and 1/8 juniors; the rest are seniors. What fraction of the class is seniors?

Firlakuza [10]

Answer:

2/8

Step-by-step explanation:

freshman=4/8

1/8 soph 1/8 jr

add all together u get 6/8

the rest is seniors so its 2/8

8 0

3 years ago