Here we have , Every day 10% of the liquid present in the morning in Kyle's open container will evaporate. At the end of three days, We need to find what percent of the original amount of liquid remains in Kyle's container . Let's find out:

Let's suppose initially we have 100% of liquid present so ,

At day 1:

10% of the liquid present(100%) in the morning in Kyle's open container will evaporate , So left is :

⇒ $100- \frac{100(10)}{100}$

⇒ $100-10$

⇒ $90$ %

At day 2:

10% of the liquid present(90%) in the morning in Kyle's open container will evaporate , So left is :

⇒ $90- \frac{90(10)}{100}$

⇒ $90-9$

⇒ $81$ %

At day 3:

10% of the liquid present(81%) in the morning in Kyle's open container will evaporate , So left is :

⇒ $81- \frac{81(10)}{100}$

⇒ $81-8.1$

⇒ $72.9$ %

Therefore , At the end of three days, $72.9$ % of the original amount of liquid remains in Kyle's container .

8 0

3 years ago

At which angle will the hexagon rotate so that it maps

Viefleur [7K]

Answer:

Step-by-step explanation:

3 0

3 years ago