A comparison between a function and its inverse would show that the domain and range of the original function swap. The domain of the function becomes the range of the inverse, the range of the function becomes the domain of its inverse.
Looking at ordered pairs of the function and its inverse would look like this:
(2,4) on the original function becomes (4,2) on the inverse.
While the graph of a function and its inverse are noticeably different an important thing to note is that it is merely a reflection across the line y=x.
So even though they appear different you are looking at the same relationship just as y vs. x instead of x vs. y
Answer:
-25/21
Step-by-step explanation:
m=(y2-y1)/(x2-x1)=(15-(-10))/(-15-6)=(15+10)/-21=25/-21
The Choice D is the best answer by the passage because it most clearly and concisely combines the sentences using the correct punctuation. This choice eliminates unnecessary words, and the commas are placed correctly between the clauses.
According to the statement
we have to find that the out of given options which is correct for replace the words in the passage.
So, For this purpose, we know that the
In the passage ,
Choice A is incorrect because the phrase “the result being that it” is wordy and could be replaced with the single word “which.” Choice B is incorrect because the words “algal blooms cause oxygen depletion” need not be repeated. Choice C is incorrect because there is unnecessary repetition of the words “oxygen depletion” and “algal blooms.”
So, The Choice D is the best answer by the passage because it most clearly and concisely combines the sentences using the correct punctuation. This choice eliminates unnecessary words, and the commas are placed correctly between the clauses.
Learn more about passage here
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Answer:
The answer is p= 2 and 1/3
Step-by-step explanation:
This answer can be found using the order of operations to solve for p.
Start by distributing 2/3 by (5p-6)
add -4/3p to 10/3p equaling 6/3p or 2p
subtract 13 from both sides
-p= 2p - 7
p=2 and 1/3
Answer:
The music director can make 15 groups of performers with 6 sixth grade students and 5 seventh grade students in each group.
Step-by-step explanation:
A school chorus has 90 sixth-grade students and 75 seventh-grade students.
Factor these two numbers:
Find GCF(90,75):
Now,
Therefore, the music director can make 15 groups of performers with 6 sixth grade students and 5 seventh grade students in each group.
