C is the answer i think but we dont see th graph
Find a common denominator which woukd be 6. imagine he divided the pie ibto 6 slices and he ate 1/2 of the pie so there are 3 slices left. after dinner he ate a third of what was left so he ate 1 slice. 1 slice out of 6 slices is 1/6
Answer:
the answer is B
Step-by-step explanation:
<em>ik because i got it right.</em>
Answer:
Step-by-step explanation:
First, we write the rental cost with each company:
Company A
Company B
Where m: miles travelled
Now, we need to find "number of miles in a day at which the rental costs for Company A and Company B are the same". This means Pa = Pb. Then:
Solving the equation for m by taking 0.2m and 60 on both sides:
Finally, dividing 0.5 on both sides:
Answer:
0.073 = 7.3% probability that a randomly selected student produces either less than 620 or more than 700 pounds of solid waste
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 650 pounds and a standard deviation of 20 pounds.
This means that
What is the probability that a randomly selected student produces either less than 620 or more than 700 pounds of solid waste?
Less than 620:
pvalue of Z when X = 620. So
has a pvalue of 0.0668
More than 700:
1 subtracted by the pvalue of Z when X = 700. So
has a pvalue of 0.9938
1 - 0.9938 = 0.0062
Total:
0.0668 + 0.0062 = 0.073
0.073 = 7.3% probability that a randomly selected student produces either less than 620 or more than 700 pounds of solid waste