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mestny [16]
3 years ago
6

An animal shelter has a 65% adoption rate for puppies. Of all puppies in the shelter, 75% live to be 7 years or older. Of the pu

ppies who are adopted, 80% live to be 7 years or older. What is the probability that a randomly selected puppy in the shelter will get adopted and live 7 or more years
Mathematics
1 answer:
Hatshy [7]3 years ago
5 0

Answer:

52% probability that a randomly selected puppy in the shelter will get adopted and live 7 or more years

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: A puppy is adopted.

Event B: The puppy lives 7 or more years.

An animal shelter has a 65% adoption rate for puppies

This means that P(A) = 0.65

Of the puppies who are adopted, 80% live to be 7 years or older.

This means that P(B|A) = 0.8

What is the probability that a randomly selected puppy in the shelter will get adopted and live 7 or more years

P(B|A) = \frac{P(A \cap B)}{P(A)}

P(A \cap B) = P(A)*P(B|A)

P(A \cap B) = 0.65*0.8

P(A \cap B) = 0.52

52% probability that a randomly selected puppy in the shelter will get adopted and live 7 or more years

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Two weeks in a row, the golf course hosts a group of golfers. The second week had 10 more golfers than the first week. Use the d
Trava [24]

Answer:

Option A.

Step-by-step explanation:

From the first dot plot the given data set for week 1 is

62, 68, 68, 68, 69, 70, 70, 72, 72, 72, 75, 75, 76, 78, 78, 80, 80, 80, 89, 89

Divide the data in 4 equal parts.

(62, 68, 68, 68, 69), (70, 70, 72, 72, 72), (75, 75, 76, 78, 78), (80, 80, 80, 89, 89)

Range=Maximum-Minimum=89-62=27

Median=\frac{72+75}{2}=73.5

Mean=\frac{\sum x}{n}=\frac{1491}{20}=74.55

From the second dot plot the given data set for week 2 is

62, 68, 68, 68, 69, 70, 70, 72, 72, 72, 75, 75, 76, 78, 78, 80, 80, 80, 85, 86, 86, 86, 88, 88, 88, 88, 89, 89, 89, 89

Divide the data in 4 equal parts.

(62, 68, 68, 68, 69, 70, 70), 72, (72, 72, 75, 75, 76, 78, 78), (80, 80, 80, 85, 86, 86, 86), 88, (88, 88, 88, 89, 89, 89, 89)

Range=Maximum-Minimum=89-62=27

Median=\frac{78+80}{2}=79

Mean=\frac{\sum x}{n}=\frac{2364}{30}=78.8

The range for Week 1 is equal to the range for Week 2.

The median for Week 2 is more than the median for Week 1.

The mean for Week 2 is more than the mean for Week 1.

Therefore, the correct option is A.

6 0
3 years ago
HELP ASAP PLEASE!!
Korolek [52]

Answer:

you can check on a website called "desmos graphing."

3 0
3 years ago
What’s the correct answer for this?
cricket20 [7]

Answer:   a

Step-by-step explanation:

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n200080 [17]

Answer:

84

Step-by-step explanation:

To find the range, find the difference between the largest value and the smallest value.

544 - 460 = 84

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3 years ago
What is the difference of 938.65−46.17?
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Look in the picture 
i showed all the work

4 0
3 years ago
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