36/39 or 12/13 is th answer to that
<span>Exactly 8*pi - 16
Approximately 9.132741229
For this problem, we need to subtract the area of the square from the area of the circle. In order to get the area of the circle, we need to calculate its radius, which will be half of its diameter. And the diameter will be the length of the diagonal for the square. And since the area of the square is 16, that means that each side has a length of 4. And the Pythagorean theorem will allow us to easily calculate the diagonal. So:
sqrt(4^2 + 4^2) = sqrt(16 + 16) = sqrt(32) = 4*sqrt(2)
Therefore the radius of the circle is 2*sqrt(2).
And the area of the circle is pi*r^2 = pi*(2*sqrt(2)) = pi*8
So the area of the rest areas is exactly 8*pi - 16, or approximately 9.132741229</span>
F(x+h) = 2(x+h) +3= 2x + 2h +3
f(x) = 2x + 5
f(x+h) - f(x) = 2x + 2h + 3- 2x - 3= 2h
[f(x+h) - f(x)]/h = 2h/h = 2
Segment BD equals 12<span />
When you roll two numbers you have four kinds of outcomes: EE, EO, OE, OO (where E = even, O = odd).
You get an even sum only if you sum two numbers that are both even or both odd, therefore the outcomes wanted are two: EE and OO.
Therefore:
P(sum is even) = 2 / 4 = 0.5
Hence, there is a 50% probability that, when you roll two numbers, their sum will be even.
